Answer: 15
Step-by-step explanation: anything in those two straight lines is automatically positive
Y+3=2(x-5)
y+3=2x-10
y+3+10=2x
y+13=2x
2x-y=13
Answer:
The value of the y-coordinate is -706
Step-by-step explanation:
The equation of a straight line is;
y = mx + c
where m is slope and c is t-intercept
Given the slope, we can write the equation as;
y = -79x + c
we need to get c
Just put in the x and y values of the given point
X = -6 and y = 5
5 = -79(-6) + c
5 = 474 + c
c = 5-474 = -469
So the complete equation of the line would
be ;
y = -79x - 469
To get the y-coordinate of the point, just insert the x value into the equation;
y = -79(3) - 469
y = -237 - 469 = -706
Answer: the first one is C
the second one is B
The standard form of the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle, (x,y) is a point of the circle, and r is the length of the radius of the circle. When the equation of a circle is written, h,k, and r are numbers, while x and y are still variables. (x-2)^2 + (y-k)^2 = 16 is an example of a circle. The problem gives us two of the three things that a circle has, a point (5,9) and the center (-2,3). We need to find the radius in order to write the equation. We substitute -2 for h, 3 for k, 5 for x, and 9 for y to get (5 - (-2))^2 + (9 - 3)^2 = r^2 We simplify: 49 + 36 = r^2, r^2 = 85. We only need to know r^2 because the equation of a circle has r^2. We now have all the information to write the equation of a circle. (x + 2)^2 + (y - 3)^2 = 85.
