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VladimirAG [237]
3 years ago
7

What is the scale factor of two regular pentagons that have areas of 50cm square and 162cm square.

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

(m/n)

Step-by-step explanation:

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A=(2 3)<br> (-1 4)<br><br> Calculate A^2-6A+11I
disa [49]

Answer:

A² - 6A + 11 I = \left[\begin{array}{ccc}0&0\\0&0\end{array}\right]

Step-by-step explanation:

Given the matrix

A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]

Calculate A² - 6A + 11 I

A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]

6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]

11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]

∴ A² - 6A + 11 I = \left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]

8 0
3 years ago
Jim drives at a speed of 50 miles per hour.<br> How long will it take to drive 125 miles?
omeli [17]
1 hour and a half
I hope it’s right
6 0
3 years ago
Read 2 more answers
What is 7/9 ÷ 1/3 plz help ​
murzikaleks [220]

Answer: 7/3

Step-by-step explanation:

To divide fractions, you can use the "keep, change, flip" method.

1. Keep the first fraction (7/9) as is.

2. Change the division sign to a multiplication sign.

3. Flip the second fraction (i.e. find the reciprocal). This means 1/3 changes to 3/1.

Rewrite the equation:

7/9 x 3/1

Multiply the numerators and the denominators together, respectively.

21/9

Simplify:

7/3

6 0
3 years ago
Read 2 more answers
Explain how you can solve 8x8 if you know how to multiply with 4 but not how to multiply with 8
Mice21 [21]
You can add 8, eight times
7 0
4 years ago
a rectangle has a perimeter of 204 feet. Its length is six feet longer that twice its width. find the dimensions
frutty [35]

<u>Answer</u>:

The length of the rectangle is 70 cm

The width of the rectangle is 32 cm

Step-by-step explanation:

<u>Given:</u>

perimeter of the rectangle  =   204 feet

Its length is six feet longer that twice its width

<u>To Find:</u>

The  dimensions of the rectangle = ?

<u>Solution:</u>

Let the width of the rectangle be x

Then its length  is six feet longer that twice its width.

That is length  = 6 + 2x

Now we know that the perimeter of the rectangle is

perimeter =  2(length + width)

204 = 2(6+2x+x)

204 = 2(6+3x)

204 = 12 +6x

204 - 12 = 6x

192 =  6x

x =\frac{192}{6}

x = 32

Thus the width is 32 cm

Its length is  

=6 + 2x

=6 + 2(32)

=6 + 64

= 70 cm

6 0
3 years ago
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