Answer:
A² - 6A + 11 I = ![\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given the matrix
![A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D)
Calculate A² - 6A + 11 I
![A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%20%3D%20A%2AA%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%2A2-3%2A1%262%2A3%2B3%2A4%5C%5C-1%2A2-4%2A1%26-1%2A3%2B4%2A4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2618%5C%5C-6%2613%5Cend%7Barray%7D%5Cright%5D)
![6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]](https://tex.z-dn.net/?f=6A%3D6%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2618%5C%5C-6%2624%5Cend%7Barray%7D%5Cright%5D)
![11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]](https://tex.z-dn.net/?f=11%20I%20%3D%2011%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%260%5C%5C0%2611%5Cend%7Barray%7D%5Cright%5D)
∴ A² - 6A + 11 I = ![\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2618%5C%5C-6%2613%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2618%5C%5C-6%2624%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%260%5C%5C0%2611%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
1 hour and a half
I hope it’s right
Answer: 7/3
Step-by-step explanation:
To divide fractions, you can use the "keep, change, flip" method.
1. Keep the first fraction (7/9) as is.
2. Change the division sign to a multiplication sign.
3. Flip the second fraction (i.e. find the reciprocal). This means 1/3 changes to 3/1.
Rewrite the equation:
7/9 x 3/1
Multiply the numerators and the denominators together, respectively.
21/9
Simplify:
7/3
<u>Answer</u>:
The length of the rectangle is 70 cm
The width of the rectangle is 32 cm
Step-by-step explanation:
<u>Given:</u>
perimeter of the rectangle = 204 feet
Its length is six feet longer that twice its width
<u>To Find:</u>
The dimensions of the rectangle = ?
<u>Solution:</u>
Let the width of the rectangle be x
Then its length is six feet longer that twice its width.
That is length = 6 + 2x
Now we know that the perimeter of the rectangle is
perimeter = 2(length + width)
204 = 2(6+2x+x)
204 = 2(6+3x)
204 = 12 +6x
204 - 12 = 6x
192 = 6x
x =
x = 32
Thus the width is 32 cm
Its length is
=6 + 2x
=6 + 2(32)
=6 + 64
= 70 cm