How do you find the solutions to a system of equations involving quadratic functions and other functions?

1 answer:

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Since no example is being given, let's take for instance 2 functions, one quadratic & the second linear:

y₁=ax²+bx+c & the second y₂=mx+b

The solution of those function is the coordinates (x,y) where both meet at a point . In this case (& in all other cases) you have to state that y₁=y₂

ax²+bx+c = mx + b & solve

example

y₁= x²+3x-1 & y₂=x-2

x²+3x-1 = x-2==>x²+3x-1-x+2 = x²+2x+1

Find the root of x²+2x+1 & you will find x'=x" -1
We have found the value of x= - 1, to find y, just plug into any of the equation x by its value & you will find y=-3
So the solution of this system of equation is at their pint(s) of intersection, that is (-1,-3)

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A can of soda is placed inside a cooler. As the soda cools, its temperature T(x) in degrees Celsius is given by the following ex

Lana71 [14]

Answer:

Ans: -21.87 ≅ -22°C

Step-by-step explanation:

T(x)=-22+44e^-0.03x

Initial temperature (x = 0):

T(0) = = -22 + 44e-0.03(0) = -22 + 44(1) = 22°C

After 18 minutes (x = 18):

T(18) = -22 + 44e-0.03(18) = -21.87°C ≅ -22°C

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