I'm assuming that when you wrote "(7x/2-5x+3)+(2x/2+4x-6)," you actually meant "(7x^2-5x+3)+(2x^2+4x-6). Correct me if I'm wrong here.

+(7x^2-5x+3)
+(2x/2+4x-6)
-------------------
=9x^2 - x - 3 (answer)

5 0

3 years ago

A certain dodgeball court is a circle with a square perfectly inscribed inside it. the square represents the playing field, whil

cluponka [151]

Exactly 8*pi - 16
Approximately 9.132741229 For this problem, we need to subtract the area of the square from the area of the circle. In order to get the area of the circle, we need to calculate its radius, which will be half of its diameter. And the diameter will be the length of the diagonal for the square. And since the area of the square is 16, that means that each side has a length of 4. And the Pythagorean theorem will allow us to easily calculate the diagonal. So: sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 4*sqrt(2) Therefore the radius of the circle is 2*sqrt(2). And the area of the circle is pi*r^2 = pi*(2*sqrt(2)) = pi*8 So the area of the rest areas is exactly 8*pi - 16, or approximately 9.132741229

6 0

3 years ago