If x>4, then the quantity x-3 inside the absolute value symbol is already positive. So, in this case, |x-3| => x-3, and x-3 is all you need to write.
Answer: d = 0
Step-by-step explanation:
5d - 4 = 4 - d
+d +d
____________
6d - 4 = 4
-4 -4
__________
6d = 0
__ __
6 6
d = 0
Answer:
11.313708498984760390413509793678 (round that)
Step-by-step explanation:
use pythag thorem, a^2 + b^2= c^2
a is 8 and b is 8 so square both and add them 64+64= 128
then take square root of 128 to find length c
and you get 11.313708498984760390413509793678
you are welcom
