The integers divisible by any set of positive
integers are the multiples of their LCM
let us first write the factored form of each
10 = 2×5
12 = 2×2×3
16 = 2×2×2×2
18 = 2 x3×3
Now we will find lcm of these numbers
LCM = 2×2×2×2×3×3×5 = 720
The multiples of 720 are divisible by 10,12,16 and 18.
2000/720 = 2.777777...
The least integer greater than that is 3, so 3×720 = 2160 is
the least integer greater than 2000 that is divisible by
10,12,16 and 18.
so if we need to find what must be added to 2000 so that the sum is divisible by 10,12,16 and 18, we must subtract 2000 from 2160
2160-2000=160
so we must add 160 to 2000 so that the sum is divisible exactly 10,12,16and 18
200 times 9 equals 1800 :)
The answer t our question is the first one
I just substituted he number one in every x
The original equation is equal to 147 when x equals to 1
And the first option is also equal to 147 when x equals to one
Answer:
Step-by-step explanation:
theres 4reds every 50 so do 50x4 then you times that by four 50x4=200 so do 200x4=800
Your answer is h (20’mm) x^c’’
