39.5 %
39.5 / 100
39 1/2 / 100
79/2 / 100
79 / 200
Answer:
The answer is actually 2
Step-by-step explanation:
No. of koolaids Kip has = 3
No. of koolaids he drank = 1
No. of koolaid doses left = 3 - 1 = 2
Answer:
The confidence interval is 6.6<μ<6.8.
Step-by-step explanation:
We have:
Number of observations = 601
Mean = 6.7
Standard deviation σ = 1.5
The z-score for a 95% confidence interval is 1.96.
The limits of the confidence interval can be calculated as

The confidence interval is 6.6<μ<6.8.
We have that
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok