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ollegr [7]
3 years ago
7

Here is the question. 100 points plz help

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

The area of the shaded region is the quarter circle minus the isosceles right triangle. The area of quarter-circle is pi*r^2/4=pi*8^2/4=16pi. The area of triangle is 8*8/2=32, so the area is 16pi-32.

The perimeter of the shaded region is the length of arc plus the segment. The length of arc is pi*2r/4=pi*16/4=4pi, and the length of the segment is 8*\sqrt(2) according to pythagorean's theorem. The total perimeter is 4pi+8*\sqrt(2).

Step-by-step explanation:


pochemuha3 years ago
7 0
The area of the shaded region is the quarter circle minus the isosceles right triangle. The area of quarter-circle is pi*r^2/4=pi*8^2/4=16pi. The area of triangle is 8*8/2=32, so the area is 16pi-32.
The perimeter of the shaded region is the length of arc plus the segment. The length of arc is pi*2r/4=pi*16/4=4pi, and the length of the segment is 8*\sqrt(2) according to pythagorean's theorem. The total perimeter is 4pi+8*\sqrt(2).
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\bf \left. \cfrac{dy}{dx}=2x \right|_{x=2}\implies 4\impliedby \textit{this means }
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\uparrow \\
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\end{array}

so we have y = 4x + b

now, recall, for the quadratic, when x =2, y = 4, so for the linear, when x = 2, y = 4 as well, this means

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\\\\\\
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check the picture below.

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hope it helps you

Step-by-step explanation:

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Step-by-step explanation:

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