The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
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Answer:
x = 9 and ∠ B = 40°
Step-by-step explanation:
See the diagram given with the question first.
Here we have ∠ A = ∠ B {They are corresponding angles}
Now, it is given that ∠ A = 5x - 5 and ∠ B = 3x + 13
Hence, 5x - 5 = 3x + 13
⇒ 2x = 18
⇒ x = 9
Therefore, ∠ B = 3x + 13 = 3(9) + 13 = 40° (Answer)
Answer:
1.C
2.A
3.D
4.C
5.B
6.A
Step-by-step explanation:
Step-by-step explanation:
13×4/9=52/9
answer as improper fraction is 52/9
Answer:
-16x + 14 4/5
Step-by-step explanation:
Perform the indicated multiplication. We get:
2x + 14 - 18x + 4/5
Next, combine like terms: We get:
-16x + 14 4/5
