19) In the xy-plane, what is the y-intercept of the graph of the equation y=3(x-1)(x+2)?

Mathematics

1 answer:

Dahasolnce [82]4 years ago

3 0

Answer:

- 6

Step-by-step explanation:

Given

y = 3(x - 1)(x + 2) ← expand factors using FOIL

= 3(x² + x - 2) ← distribute by 3

= 3x² + 3x - 6

To find the y- intercept let x = 0, thus

y = 3(0)² + 3(0) - 6 = 0 + 0 - 6 = - 6

Thus y- intercept = - 6 ⇒ (0, - 6 )

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I don't get it plz help

Salsk061 [2.6K]

Just use the order of operations. PEMDAS, parentheses, exponents, multiplication, division, addition and subtraction.

In the first problem 2 + 6*3^2, there are no parentheses, so next would be exponents.
There is an exponent so you do that first.
3^2 = 9

Now we have 2 + 6*9
Multiplication is next and it is in the problem, so we do 6*9 = 54
So now we have 2 + 54 which equals 56.

6 0

4 years ago

Read 2 more answers

BRAINLIESTT ASAP! PLEASE HELP ME :)

Anvisha [2.4K]

Step-by-step explanation:

$\displaystyle y = Asec(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the midline where the amplitude is. Moreover, ALL tangent, secant, cosecant, and cotangent functions have NO AMPLITUDE.

I am joyous to assist you anytime.