Answer:
Step-by-step explanation:

Answer:
1 ≥ t ≤ 3
Step-by-step explanation:
Given
h(t) = -16t² + 64t + 4
Required
Determine the interval which the bar is at a height greater than or equal to 52ft
This implies that
h(t) ≥ 52
Substitute -16t² + 64t + 4 for h(t)
-16t² + 64t + 4 ≥ 52
Collect like terms
-16t² + 64t + 4 - 52 ≥ 0
-16t² + 64t - 48 ≥ 0
Divide through by 16
-t² + 4t - 3 ≥ 0
Multiply through by -1
t² - 4t + 3 ≤ 0
t² - 3t - t + 3 ≤ 0
t(t - 3) -1(t - 3) ≤ 0
(t - 1)(t - 3) ≤ 0
t - 1 ≤ 0 or t - 3 ≤ 0
t ≤ 1 or t ≤ 3
Rewrite as:
1 ≥ t or t ≤ 3
Combine inequality
1 ≥ t ≤ 3
There all kinds so it would keep going on with nines
The square root of 195 is 13. 195 squared (195×195) is 38,025. I do not know which way you needed it but I put both situations just in case.
Answer:
y = 4x - 7
Step-by-step explanation:
Slope = 4 ; x1 = 2 , y1 = 1
Slope point form: y -y1 = m(x -x1)
y - 1 = 4(x - 2)
y - 1 = 4x - 2*4
y -1 = 4x - 8
y = 4x - 8 +1
y = 4x - 7