Since there are no figures given, I will give an example.
You are given a silo that is shaped as
a closed cylinder with a conical end. The diameter of the silo is 4 ft, the
length of the cylindrical part is 6 ft, and the entire length of the silo is
10.5 ft. Suppose that you are asked to find the total volume of
grains that can be stored in the silo.
Given:
Cylinder part
D = 4 ft
H = 6 ft
Cone part
H = 10.5 – 6 = 4.5ft
D = 4ft
Required:
Volume of silo
Solution:
V of cylinder = πr²H
V of cylinder = π(4/2)²(6)
V of cylinder = 75.4 ft³
V of cone = πr²H/3
V of cone = π(4/2)²(4.5/3)
V of cone = 18.85 ft³
Total volume = 94.25 ft³
Answer:
y = 10
Step-by-step explanation:
Using the sine ratio in the right triangle and the exact value
sin30° = 
, then
sin30° = 
= 
= ( cross- multiply )
2y = 20 ( divide both sides by 2 )
y = 10
Answer:
m (2,6), L (3, -6), J (-6, -9), K (-1, -9)
Step-by-step explanation:
The correct answer is <span>C. Lines m and n have the same slope so they are parallel. The slope = 2/3 </span>
Answer:
The correct answer is there are 15 samples each of size 4 to choose from the population and the population mean is 27.
Step-by-step explanation:
Total number of lottery tickets = 6
Number of samples of size 4 that can be drawn from this population of 6 lottery numbers are = ![\left[\begin{array}{ccc}6\\4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C4%5Cend%7Barray%7D%5Cright%5D)
= 15.
Now the population mean is given by 
× ∑ x , where n is the number of lottery tickets and ∑ x is the sum of the lottery numbers.
Summation of the lottery ticket numbers is 162
Thus the population mean is given by 
= 27.
