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Murrr4er [49]
4 years ago
6

What's the answer to this I'm stuck?

Mathematics
1 answer:
Roman55 [17]4 years ago
8 0

16. The expression is 20-4, or 20+(-4). The answer is 16 ft.

17. The expression is 4(6). The answer is $24.

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Identify the coordinate of the point (-7,-5) under a rotation of 180° clockwise about the orgin
dolphi86 [110]
P(x,y)\xrightarrow{\text{rotation(origin,180)}}P'(-x,-y)\\\\
P(-7,-5)\xrightarrow{\text{rotation(origin,180)}}P'(7,5)

5 0
3 years ago
C. How can you use the area of the square to find the side length?
Kruka [31]

Answer:

Step-by-step explanation:

Since squares are the same length on each side, whatever one side is, if you square it, it will give you the area of the square. To find the length of one side, you need to do the inverse: find the square root of the area.

for example: if you have a square that is 3x3, the are is 3², or 9. Now, in order to find the length of one side, you need to do √9, which gives you 3.

5 0
3 years ago
Which of the following functions is graphed below?
katrin2010 [14]

Answer:

B. y = [x] + 7

Step-by-step explanation:

If you are going left on the x-axis your sign would be positive

7 0
3 years ago
Consider the following function. f(x) = 2x3 + 9x2 − 24x (a) Find the critical numbers of f. (Enter your answers as a comma-separ
viktelen [127]

Answer:

(a) The critical number of f(x) are x=-4, 1

(b)

  • Increasing for (-\infty, -4)
  • Decreasing for (-4, 1)
  • Increasing for  (1, \infty)

(c)

  • relative maximum (-4, 112)
  • relative minimum (1, -13)

Step-by-step explanation:

(a) The critical numbers of a function are given by finding the roots of the first derivative of the function or the values where the first derivative does not exist. Since the function is a polynomial, its domain and the domain of its derivatives is (-\infty, \infty). Thus:

\frac{df(x)}{dx}  = \frac{d(2x^3+9x^2-24x)}{dx} =6 x^2+18x -24\\6 x^2+18x -24=0\\\boxed{x=-4, x=1}

(b)

  • A function f(x) defined on an interval is monotone increasing on (a, b) if for every x_1, x_2 \in (a, b): x_1 implies f(x_1)
  • A function f(x) defined on an interval is monotone decreasing on (a, b) if for every x_1, x_2 \in (a, b): x_1 implies f(x_1)>f(x_2)

Combining  the domain (-\infty, \infty) with the critical numbers we have the intervals (-\infty, -4), (-4, 1) and (1, \infty). Note that any of the points are included, in the case of the infinity it is by definition and the critical number are never included because the function monotony is not defined in the critical points, i.e. it is not monotone increasing or decreasing. Now, let's check for the monotony in each interval, for this, we check for the sign of the first derivative in each interval. Evaluating in each interval the first derivative (one point is enough), we obtain the monotony of the function to be:

  • Increasing for (-\infty, -4)
  • Decreasing for (-4, 1)
  • Increasing for  (1, \infty)

(c) From the values obtained in (a) so the relative extremum are the points (-4, 112) and (1, -13). The y-values are found by evaluating the critical numbers in the original function. Since the first derivative decreases after passing through  x=-4 and increases after passing through the point x=1 we have:

  • relative maximum (-4, 112)
  • relative minimum (1, -13)

3 0
4 years ago
Which of the following are solutions. Check all that apply
kirza4 [7]

Answer: b, c

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

8 0
3 years ago
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