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Mazyrski [523]
2 years ago
13

The question is attached in the picture

Mathematics
1 answer:
Deffense [45]2 years ago
7 0

Answer:

<h2><u><em>1875</em></u></h2>

Step-by-step explanation:

25*75

 175  

  125

1875

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dusya [7]
The answer to your Q is 4
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3 years ago
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Weinstein, McDermott, and Roediger report that students who were givne questions to be answered while studying new material had
emmainna [20.7K]
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By considering the given information , we have

Null hypothesis : H_0: \mu=73.4

Alternative hypothesis :  H_a: \mu>73.4

Since alternative hypothesis is right-tailed , so the test is a right-tailed test.

Given : Sample size : n=16 , which is a small sample , so we use t-test.

Sample mean: \overline{x}=78.3  ;

Standard deviation: s=8.4

Test statistic for population mean:

t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e. t=\dfrac{78.3-73.4}{\dfrac{8.4}{\sqrt{16}}}\approx2.333

Using the standard normal distribution table of t , we have

Critical value for \alpha=0.01 : t_{(n-1,\alpha)}=t_{(15,0.01)}=2.602

Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.

3 0
3 years ago
How many milliequivalents of sodium chloride are contained with 3 L of normal saline?
AVprozaik [17]

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

3000ml*\frac{0.9g}{100ml}=27g=27000mg

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation (mEq=\frac{mg}{pE}) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

pE= \frac{23+35}{1}=\frac{58}{1} = 58

Finally we substitute in the mEq formula:

mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq

I hope you find this information useful! Good luck!

4 0
3 years ago
A television Mark 1600 was sold for 1200 what percent discount was given on that television​
adoni [48]

Answer:

25%

Step-by-step explanation:

Discount = 1600 - 1200 = 400

Percentage discount

=  \frac{400}{1600}  \times 100 \\  \\  =  \frac{400}{16}  \\  \\  = 25\%

5 0
2 years ago
Which of the following is not a rational number?
IceJOKER [234]

Answer:

Option D is not a rational number

Step-by-step explanation:

A rational number is one that can be represented in the form of fraction like X/Y, where X and Y are integers and X ≠ 0. While an irrational number is one that cannot be expressed in the form of simple fractions.

For example, ¾ is a rational number while √3 is an irrational number.

Now to the question;

A) The product of 2 and 0.3333 gives;

2 × 0.3333 = 0.6666.

This can be expressed as a fraction as; 6666/10000.

Thus it is a rational number

B) The sum of 2 + √3 and 5 - √3 gives;

2 + √3 + 5 - √3 = 7

As a fraction, it can be written as; 7/1

Thus it is a rational number.

C) The sum of 37 and 12 is;

37 + 12 = 49

Can be expressed as; 49/1

Thus,it's a rational number.

D) Product of 2 and √2 gives;

2 × √2 = 2√2

It can't be expressed as a fraction with integers. Thus, it's not a rational number.

6 0
3 years ago
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