Answer:
remember
1h=60min
1min=60 sec
now come to the question
1h=60min
1min=60 sec
60min=60×60=3600sec in 1hour
25min=60×25=1500sec in 25 min
total all sec=3600+1500+29=5129sec
Step-by-step explanation:
The temperature must rise 5 degrees to reach the original temperature
9514 1404 393
Answer:
maximum difference is 38 at x = -3
Step-by-step explanation:
This is nicely solved by a graphing calculator, which can plot the difference between the functions. The attached shows the maximum difference on the given interval is 38 at x = -3.
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Ordinarily, the distance between curves is measured vertically. Here that means you're interested in finding the stationary points of the difference between the functions, along with that difference at the ends of the interval. The maximum difference magnitude is what you're interested in.
h(x) = g(x) -f(x) = (2x³ +5x² -15x) -(x³ +3x² -2) = x³ +2x² -15x +2
Then the derivative is ...
h'(x) = 3x² +4x -15 = (x +3)(3x -5)
This has zeros (stationary points) at x = -3 and x = 5/3. The values of h(x) of concern are those at x=-5, -3, 5/3, 3. These are shown in the attached table.
The maximum difference between f(x) and g(x) is 38 at x = -3.
All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!
Answer:
-3/56
Step-by-step explanation:
-1/5 ab
Let a = 3/7 b = 5/8
-1/5 * 3/7 * 5/8
Rewriting
-1/7 * 3/8 * 5/5
Canceling like terms and multiplying
-3/56