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DENIUS [597]
3 years ago
7

Umm plz help with just the first part

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

Factored form: -2(x + 7) = 8, x = -11 (brainliest)?

Step-by-step explanation:

-2(x + 7) = 8

x + 7 = 8 / -2

x + 7 = -4

x = -4 - 7

= -11

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What is the answer for <br> an=an–1+1
Gekata [30.6K]

Answer:

Step-by-step expla2nation:

7 0
3 years ago
The circle below is centered at the point (4,1) and has a radius of length 2. What is it’s equation?
vekshin1

Answer:

Option B:

(x-4)^2+(y-1)^2 = 4

Step-by-step explanation:

Given

Centre = (h,k) = (4,1)

Radius = r = 2

The standard equation of circle is:

(x-h)^2+(y-k)^2=r^2

Putting the values of h,k and r

(x-4)^2+(y-1)^2 = (2)^2\\(x-4)^2+(y-1)^2 = 4

Hence, the correct option is option B

(x-4)^2+(y-1)^2 = 4

5 0
3 years ago
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Simplify the expression given below: (18x^3-7)-(14x^3-36)
vovangra [49]

Answer:

2x6 + 4x5 + x4 + 11x3 + 2x2 + 4x + 4

Step-by-step explanation:

6 0
2 years ago
The perimeter of a regular hexagon is ninety-six centimetres. Find the length of each side.​
rusak2 [61]

Answer:

54cm, which is one side length

Step-by-step explanation:

The sum of all of the sides are 6, it's a regular hexagon the perimemter is just six times one side 36cm

Hope It Helps!

8 0
3 years ago
Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

since cosec x = 1/sinx

1/sinx = 4

sinx = 1/4

From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

sin2x = 2(1/4)(√15/4)

sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

5 0
3 years ago
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