hello :
the area of the circle is : 40 cm²
40 = <span>πr²
r² = 40/(3.14 )
r² = 12.73 cm</span>
For this case we have that by definition, the area of a square is given by:
Where:
l: It's the side of the square
We have, according to the statement data, that:
Then, the area is given by:
By definition of power properties we have to:
So:
Answer:
The area of the square is: 
Answer:
MQ and QP are equal, MO and OP are equal, x=2
Step-by-step explanation:
QO is a perpendicular bisector of MP meaning that Triangle MQP must be isosceles (if at least two of the following, angle bisector, median, or an altitude, coincide in a triangle, that triangle must be isosceles). In this case an altitude and median coincide in triangle MQP. This means that MQ=QP as the triangle is isosceles. And also MO=OP because QO is a median. Now solving for x, 11=4x+3, 8=4x, x=2. Hope this helps!
All you do is add up the sides of the walls, and you get your answer.
<3.
OG.
The ball hits the ground when the height h(t) = 0 , so
-16t^2 + 80t = 0
-16t(t - 5) = 0
t- 5 = 0 or -16t^2 = 0 ( here t = 0 which corresponds to when ball is thrown)
t - 5 = 0 gives:-
t = 5 seconds (answer)
