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aleksandrvk [35]
3 years ago
10

How do I solve this ?

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

13.6 years

Step-by-step explanation:

Let Ao be the initial value.  We're interested in finding out how long it will take for A to double in value, that is, become equal to 2Ao.

We get:

2Ao = Ao(1 + 0.05/12)^(12t)

and must solve this for t.

Dividing both sides by Ao yields 2 = 1(1 + 0.05/12)^(12t), or

                                                       2 = (1 + 0.00427)^(12t)

Solve for t by taking the common log of both sides:

log 2 = 12t·log (1.00427), or

0.30103 = 12·t·0.00185.  Performing the multiplication on the right side, we get

0.30103 = 0.0222t.

Dividing both sides by 0.0222, we get:

     0.30103

t = --------------------  =  13.56

             0.0222

It will take this investment about 13 1/2 years to double in value.

Rounded to the nearest tenth, that'd be 13.6 years.

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What is the value of the sum of all the terms of the geometric series 300, 60, 12, …?
ruslelena [56]
<h3>Answer:   375</h3>

=========================================

Work Shown:

a = 300 = first term

r = 60/300 = 0.2 = common ratio

We multiply each term by 0.2, aka 1/5, to get the next term.

Since -1 < r < 1 is true, we can use the infinite geometric sum formula below

S = a/(1-r)

S = 300/(1-0.2)

S = 300/0.8

S = 375

----------

As a sort of "check", we can add up partial sums like so

  • 300+60 = 360
  • 300+60+12 = 360+12 = 372
  • 300+60+12+2.4 = 372+2.4 = 374.4
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and so on. The idea is that each time we add on a new term, we should be getting closer and closer to 375. I put "check" in quotation marks because it's probably not the rigorous of checks possible. But it may give a good idea of what's going on.

----------

Side note: If the common ratio r was either r < -1 or r > 1, then the terms we add on would get larger and larger. This would mean we don't approach a single finite value with the infinite sum.

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