There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.
The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.
18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.
32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.
The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.
Answer:
y=5
m<A= 25
m<E= 35
Step-by-step explanation:
since <E equals <B due to CPCTC the equation:
3y+20=10+5y
is the equation
She would by 3 packages of hot dogs and 2 packages of hot dog buns. This is because 3*8 would be 24 and 12*2 is also 24. These would both be the minimum amount of packages.
4 legged tables : x
3 legged stools : y
x + y = 20 y= 20 - x
4x + 3y = 68
Replace y by 20 - x so we only have one letter
4x + 3(20 - x) =68
4x + 60 - 3x =68
x + 60 = 68
x = 8
To find y replace x by 8
y = 20 - 8
y = 12
So you have 8 four legged chairs and 12 three legged stools.
Hope I helped!
Answer:
Step-by-step explanation:
V=Tr^2h
V / T = r^2 h
V / Th = r^2
√V / Th
