Please answer this question.
1 answer:
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Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x J
proton's mass, m = 1.673 x kg
charge, q = 1.602 x C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x J) / (1.602 x
C)(2 m)
= 1.01 x N/C
Answer:
Explanation:
We know that there is a relation between the speed of light ,frequency and wavelength.This relation can be given as where v is speed of light
is frequency of light
is wavelength of light
In first case we have given λ=655 nm
so using formula
Hz
In second case we have wavelength 515 nm so by using above formula
In third case we have wavelength 475 nm
so
Given k=100, Area if plate A = 1.00 cm2
Thickness of rutile
Without any dielectric medium capacitance of a parallel plate capacitor is c = oAd
When a dielectric is placed between capacitors plates then capacitance c1 = KoAd
Here ,
Now
Correct Option: A
What purposes serve parallel plate capacitors?
The following are some uses for parallel plate capacitors:
- This kind of capacitor is utilized in rechargeable energy systems such as batteries.
- These capacitors are used in systems for dynamic digital memory.
- Such capacitors are used in pulsed laser and radar circuits.
To learn more about Parallel plate capacitors, visit:
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