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Lostsunrise [7]
2 years ago
15

Plsss help me!!!!!!!!!

Physics
1 answer:
natali 33 [55]2 years ago
6 0
It should be the B
Low frequency and long wavelength
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A 2.0-kg pistol fires a 1.0-g bullet with a muzzle speed of 1000 m/s. The bullet then strikes a 10-kg wooden block resting on a
Andreyy89

Answer:

1000 N

Explanation:

An impulse results in a change of momentum

FΔt = mΔv

F = 0.001 kg(1000 - 0) m/s / 0.001 s = 1000 N

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3 years ago
A man walks 30 m to the west, then 5 m to the east in 45 seconds.
katen-ka-za [31]

Answer:

a. Displacement=30²+5²=925= 30.4m

b. Total distance=30m+5m=35m

c. V=s/t. = 30.4/45=0.6m/s

8 0
1 year ago
An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal
joja [24]

Complete Question

An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters )  is the airplane above the ground 13 seconds after takeoff?

Answer:

The height  is H  =  318.5 \ m

Explanation:

From the question we are told that

   The speed at which the plane takes off is  u = 49 \ m/s

      The angle at which it takes off is  \theta  =  30 ^o

        The time taken is t =  13  s

The vertical distance traveled is  mathematically represented as

          H  =  u sin  \theta  t

Substituting values  

         H  =  (49) * sin (30) *13

        H  =  318.5 \ m

6 0
3 years ago
Answer the question below based on the periodic table entry for bromine.
Sphinxa [80]
The answer is 45 i hope i could help
8 0
3 years ago
Read 2 more answers
A 0.500 H inductor is connected in series with a 93 Ω resistor and an ac source. The voltage across the inductor is V = −(11.0V)
bezimeni [28]

Answer:

205 V

V_{R} = 2.05 V

Explanation:

L = Inductance in Henries, (H)  = 0.500 H

resistor is of 93 Ω so R = 93 Ω

The voltage across the inductor is

V_{L} = - IwLsin(wt)

w = 500 rad/s

IwL = 11.0 V

Current:

I = 11.0 V / wL

 = 11.0 V / 500 rad/s (0.500 H)

 = 11.0 / 250

I = 0.044 A

Now

V_{R} = IR

    = (0.044 A) (93 Ω)

V_{R} = 4.092 V

Deriving formula for voltage across the resistor

The derivative of sin is cos

V_{R} = V_{R} cos (wt)

Putting V_{R} = 4.092 V and w = 500 rad/s

V_{R} = V_{R} cos (wt)

    = (4.092 V) (cos(500 rad/s )t)

So the voltage across the resistor at 2.09 x 10-3 s is which means

t = 2.09 x 10⁻³

V_{R} = (4.092 V) (cos (500 rads/s)(2.09 x 10⁻³s))

    =  (4.092 V) (cos (500 rads/s)(0.00209))

    = (4.092 V) (cos(1.045))

    = (4.092 V)(0.501902)

    = 2.053783

V_{R} = 2.05 V

8 0
3 years ago
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