Question

A particle beam is made up of many protons, each with a kinetic energy of 3.25times 10-15 J. A proton has a mass of 1.673 times 10-27 kg and a charge of +1.602 times 10-19 C. What is the magnitude of a uniform electric field that will stop these protons in a distance of 2 m?

Answer 1

Answer:

The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x $10^{-4}$ N/C

Explanation:

given information,

kinetic energy, KE = 3.25 x $10^{-15}$ J

proton's mass, m = 1.673 x $10^{-27}$ kg

charge, q = 1.602 x $10^{-19}$ C

distance, d = 2 m

to find the electric field that will stop the proton, we can use the following equation:

E = F/q

   = (KE/d) / q ,        KE = Fd --> F = KE/d

   = KE/qd

    = (3.25 x $10^{-15}$ J) / (1.602 x $10^{-19}$ C)(2 m)

    = 1.01 x $10^{-4}$ N/C