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3 years ago

Solve for y. x+y=7 x=4 Simplify your answer as much as possible.

Mathematics

2 answers:

horsena [70]3 years ago

7 0

Answer:

The answer is y = 3

hope this helped :)

allsm [11]3 years ago

6 0

Answer is 3 because look 4+y=7
7 - 4 = 3
4+y=7

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18.85

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N is an integer, write down the values of n such that -15<3n<6

Ira Lisetskai [31]

-15 < 3n < 6

Divide all sides by 3

-5 < n < 2

Now you need all integers between -5 and 2.

-4, -3, -2, -1, 0, 1

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4 years ago

Help and It’s 100 points

mylen [45]

D is the correct answer the others would simply lower. 20/5 equals 4

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<img src="https://tex.z-dn.net/?f=x%5E3%5Csqrt%7B175x%5E7y%5E5%7D" id="TexFormula1" title="x^3\sqrt{175x^7y^5}" alt="x^3\sqrt{17

romanna [79]

Answer:

$5x^{6}y^{2} \sqrt{7xy}$

Step-by-step explanation:

Fistly , you have to know these :

$a\sqrt{x} + b\sqrt{x} = (a+b)\sqrt{x} \\\sqrt{a.b^{2} } =b\sqrt{a} \\ c\sqrt{a.b^{2} } =(c.b)\sqrt{a} \\a\sqrt{x} - b\sqrt{x} = (a-b)\sqrt{x}$

About your question:

 $x^{3}\sqrt{175x^{7}y^{5}}$ 

 $x^{3}\sqrt{175x^{2}.x^{2}.x^{2}.x.y^{2}.y^{2}.y}$ 

 $\sqrt{175} =\sqrt{25.7} = 5\sqrt{7}$ 

 $5x^{3}\sqrt{7.x^{2}.x^{2}.x^{2}.x.y^{2}.y^{2}.y}$ 

 $5x^{3}.x.x.x\sqrt{7.x.y^{2}.y^{2}.y}$ 

 $5x^{6}\sqrt{7.x.y^{2}.y^{2}.y}$ 

 $5x^{6}.y.y\sqrt{7.x.y}$ 

 $5x^{6}.y^{2}\sqrt{7.x.y}$ 

=> $5x^{6}y^{2} \sqrt{7xy}$ <=

Hope it helps ^-^

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3 years ago

1/2x-3=141 help me with this

Maru [420]

Answer:

1/2x-3=141

so first add 3 from both sides:

1/2x=141+3

1/2x=144

next divide is 1/2 on both sides

x=144/(1/2)

x=288

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