All categories

3 years ago

Evaluate. 46−[(9+15÷5)×3]

Mathematics

2 answers:

Dvinal [7]3 years ago

7 0

Answer:

46−[(9+15÷5)×3] = 10

Step-by-step explanation:

46-[(9+3)×3]

46-[12×3]

46-36

mojhsa [17]3 years ago

6 0

Answer:

Step-by-step explanation:

46 - [(9 + 15 ÷ 5) × 3]

~We can simplify everythingusing PEMDAS

46 - [(9 + 3) × 3]

46 - [(12) × 3]

46 - 36

Best of Luck!

You might be interested in

Jim spent $46.16 on some mulch and one shovel. Each bag of mulch costs $3.49 and the shovel cost $14.75. How many bags of mulch

mezya [45]

To find the amount he spent on bags of mulch you must take the cost of the shovel away from the total, giving the equation:
46.16-14.75=3.49x
To covert this to whole numbers, multiply by 100
4616-1475=349x
3141=349x
x=9

4 0

4 years ago

Which of the following inequalities are true

tekilochka [14]

Answer: The answer is E: |-4|<|-7| and C: |-7|>|4|

4 0

3 years ago

What are the solutions of x3>−1 ? Graph the solutions.

Ksivusya [100]

X>-1/3, the graph would be filled everything to the right of -1/3 on the x axis

5 0

3 years ago

9 is subtracted from 3 times the sum of 4 and 2

Len [333]

Answer:

Step-by-step explanation:

3 times the sum of 4 and 2 = 3*(4+2)

= 3 * 6

= 18

18 - 9 = 9

8 0

3 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$