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2 years ago

Sum of two numbers is 24 and the difference is 15.What are the two numbers ?

1 answer:

5 0

Let,
the bigger number be "x"
the smaller number be "y"
Now, according to the question,
x + y = 24...........equation (1).............because the sum of numbers is 24
x - y = 15 .............equation (2)..................because their difference is 15

Taking equation (2),
x - y = 15
x = 15 + y ....................equation (3)

Now, Taking equation (1)
x + y = 24
(Substituting the value of "x" form equation (3) we get)
15 + y + y = 24
(Subtracting 15 on both sides, we get)
y + y = 24 - 15
2y = 9
y = 9 / 2
y = 4.5
Now,
Taking equation (3)
x = 15 + y
(Substituting the value of y , we get)
x = 15 + 4.5
x = 19.5

So, the two numbers are 19.5 and 4.5

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3 years ago

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Ksivusya [100]

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= 6in : 2 = 3in

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2 years ago

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3 years ago

Two dice are tossed. Find the probability of getting the sum of the dice equal to 28.

dimulka [17.4K]

Answer:

Isn't the sum when you add numbers together? if this is true, there is no way you can get the sum of 28

Step-by-step explanation:

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3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

Step-by-step explanation:

The random variable X is defined as the number of seconds for a randomly selected lap.

The random variable X is normally distributed with mean, μ = 129.71 seconds and standard deviation, σ = 2.28 seconds.

Thus, $X\sim N(129.71,\ 2.28^{2})$ .

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

$P(X$

$=P(Z$

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let x represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of z for the above probability is:

z = -1.88

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42$

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let x₁ and x₂ be the values between which the middle 80% of the distribution lie.

That is,

$P(x_{1}$

The value of z for the above probability is:

z = 1.28

Compute the values of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80$ $z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63$

Thus, the middle 80% of her laps are from 126.80 seconds to 132.63 seconds.

5 0

3 years ago