Will mark brainliest answer, please answer !!!!

• Hari bought 25 kg of pure ghee at Rs 180 per kg and 25 kg vanaspati ghee of Rs.80 per kg. He mixed both types of ghee and sold

Basile [38]

Step-by-step explanation:

as given,

hari bought,

amount of pure ghee he bought = 25 kg

cost of pure ghee per kg = Rs. 180

so, cost of 25 kg of pure ghee = 180 × 25 = Rs 4,500

amount of vanaspati ghee = 25 kg

cost of per kg of vanaspati ghee = Rs. 80

so, cost of 25 kg of vanaspati ghee = 80 × 25 = Rs. 2,000

he mixed both the ghee and got ( 25 + 25 ) = 50 kg of mixed ghee.

he sold them in cost = Rs. 150 per kg

so, total SP of mixed ghee = 150 × 50 = Rs. 7,500

so,

total CP = ( 4500 + 2000 ) = Rs. 6,500

total SP = Rs. 7,500

so,

Profit = SP - CP

→ 7,500 - 6,500 = Rs. 1000

Profit / gain = ( gain × 100 / CP)

→ (1000 × 100 / 6,500 )

→ 1000/65 = 15.38 ( approx.)

therefore, it's a profit of 15.38%.

hope this answer helps you dear! and may u have a great day ahead! take care!

8 0

3 years ago

Plssssssssssssssssssss Answer this is Major?

julsineya [31]

Answer:

See below because there are 9 parts (A through I)

Explanation:

Part A: write an equation that models the area of the figure. Let y represent the area, and write your answer in the form y = ax2 + bx + c.

The figure shows a rectangular table with these dimensions:

Length: - x + 64
Witdth: x + 4

The area of a rectangle is width × length:

$(x + 4)\times (-x+64)$

Use distributive property:

$x\cdot (-x)+x\cdot(64)+4\cdot (-x)+4\cdot (64)=-x^2+64x-4x+256$

Simplify:

$-x^2+64x-4x+256=-x^2+60x+256$

Part B. Graph the equation you wrote in part A. Adjust the zoom of the graphing window so the vertex, x-intercepts, and y-intercept can be seen.

1. Factor the equation:

Common factor - 1:

$-x^2+60x+256=-(x^2-60x-256)$

Find two numbers that add - 60 and whose product is -256. Theyb are -64 and + 4

$-(x-64)(x+4)$

2. Find the roots:

Equal the expression to zero:

$-(x-64)(x+4)=0\\ \\ x-64=0\implies x=64\\ \\ x+4=0\implies x=-4$

Those are the x-intercepts: (-4,0) and (64,0)

3. Find the symmetry axis:

The simmetry axis is the line x = the middle value between the two roots:

$x=(64-4)/2=60/2=30$

4. Find the vertex

The vertex has x-coordinate equal to the x axis (30 in this case).

Substitute in the equation of find the y-coordinate:

$y=-(30-64)(30+4)=-(-34)(34)=1,156$

Hence, the vertex is (30, 1,156)

5. Find the y-intercept

Make x = 0

$y=-(x^2-60x-256)=-(0-256)=256$

Hence, the y-intercept is (0, 256)

With the x-incercepts, the y-intercept, the axis of symmetry, and the vertex, you can sketch the graph.

You can see now the graph in the attached figure

Part C. Extreme location of the graph

The graph shows that the parabola opens downward. That is due to the fact that the coefficient of the leading term (x²) is negative.

The parabola starts in the second quadrant. starts growing, crosses the x-axis at (-4,0), crosses the y-axis at (0,256), reaches the maximum value at (30, 1156), and then decreases toward the fouth quadrant, crossing the x-axis at (64,0).

Thus the vertex is a maximun, and the coordinates of the maximum are (30, 1156).

Part D. According to the graph, what is the maximum possible area of the game board? Give your answer to the nearest whole number. (Assume that the maximum area is not reduced by the open hole in the game board.)

The maximum possible area of the game is the maximum value of the function y = -x² + 60x + 256.

This value was calculated as y = 1156.

Part E. Use the original expressions for the length and width, and substitute the x-coordinate from the extreme location. What are the length and width of the game board at the extreme location?

The length is:

length = - x + 64 inches

x = 30

length = - 30 + 64 = 34 inches

The width is:

width = x + 4

x = 30

width = 30 + 4 = 34 inches

Part F. What type of quadrilateral will be formed when the game board covers the maximum possible area?

Since the length and the width are equal, the quadrilateral is a square.

Part G. Suppose the carnival director asks you to create a game board that is 1,120 square inches. Find the dimensions that would meet this request by setting the area equation equal to 1,120, solving for x, and substituting x into the expressions for the length and width.

$y=-x^2+60x+256\\ \\ 1,120=-x^2+60x+256\\ \\ x^2-60x-256+1120=0\\ \\ x^2-60x+864=0$

Factor:

Find two numbers whose sum is - 60 and the product os 864. They are -24 and - 34:

$x^2-60x+864=(x-24)(x-36)$

Use the zero product rule:

$(x-24)(x-36)=0\\ \\ x-24=0\implies x=24\\ \\ x-36=0\implies x=36$

Now substitute to find the dimensions:

x = 36

length = - x + 64

length = - 36 + 64 = 28

width = x + 4 = 36 + 4 = 40

Hence, legth = 28, width = 40

x = 24

length = - x + 64 = -24 + 64 = 40

width = x + 4 = 24 + 4 = 28

Part H. When you solved the area equation for x, did any extraneous solutions result? Describe how an extraneous solution would arise in this situation.

The two solutions are valid (non extraneous) because both leads to positive real dimensions for which the areas can be 1,120 in².

28×40 = 1,120

40×28 = 1,120

An extraneous solution could arise if you try to find areas for which x is greater than or equal to 64, because in that case - x + 64 would be zero or negative and dimensions must be positive.

For the same reason, also an extraneous solution would arise if you try to fix areas for which x is less than or equal to - 4.

So, the domain of your function has to be - 4 < x < 64.

Part I. What method of solving quadratics did you use to solve the equation set equal to 1,120? Why did you choose this method?

The method use was factoring.

Discuss the usefulness of other methods of solving quadratics as they pertain to this scenario.

The other importants methods are graphical and the quadratic equation.

For graphical method you graph your parabola and find the values of x that sitisfies the area searched (value of y).

The quadratic equation gives the y-values (areas) without factoring:

$\frac{-b+/-\sqrt{b^2-4(a)(c)} }{2(a)}$

8 0

3 years ago

How would you write a word phrase for the algebraic expression d/5+2? The difference between the quotient of d and 5 and 2? The

krek1111 [17]

Answer: The word phrase for this expression is the last option, "The sum of the quotient of d and 5 and 2." d is being divided by 5, so we would use "quotient of d and 5" for that part, and then we would add the "sum" because d/5 is being added to 2.

5 0

3 years ago

Question 3(Multiple Choice Worth 3 points)

Marrrta [24]

Hello,

Please, see the attached file.

Thanks.

8 0

3 years ago

If ΔFGH ≅ ΔIJK, which segment is congruent to FH? PLS HELP PLS PLS PLS

Mazyrski [523]

Answer:

IK

Step-by-step explanation:

If you draw out the triangles it is easier to see

8 0

3 years ago