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4 years ago

Find the least common multiple of 12,14,and 21k

Mathematics

1 answer:

seraphim [82]4 years ago

6 0

Answer: (if you meant 21)

Step-by-step explanation:

Multiples of 12:

12, 24, 36, 48, 60, 72, 84, 96, 108

Multiples of 14:

14, 28, 42, 56, 70, 84, 98, 112

Multiples of 21:

21, 42, 63, 84, 105, 126

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If VW is 10 cm, find the length of VR⌢. Round to the nearest hundredth (two decimal places).

Assoli18 [71]

Given:

Given that the length of VW is 10 cm.

The central angle is 127°

We need to determine the arc length of VR.

Arc length of VR:

The arc length of VR can be determined using the formula,

$Arc \ length = \frac{\theta}{360}\times 2 \pi r$

Substituting $\theta=127$ and r = 10, we get;

$Arc \ length = \frac{127}{360}\times 2 (3.14)(10)$

Simplifying the terms, we get;

$Arc \ length = \frac{7975.6}{360}$

$Arc \ length = 22.154$

Rounding off to the nearest hundredth, we get;

$Arc \ length = 22.15$

Thus, the arc length of VR is 22.15 cm

3 0

3 years ago

Amelia is 17 inches long. She add 8 more inches to her line. How long is her line now?

Alenkasestr [34]

I’m going to assume that the original line she had was 17 inches long. Since she ADDED 8 to the original line, just add:

17 + 8 = 25

Therefore, her line is now 25 inches.

Best of Luck!

6 0

3 years ago

Write the prime factorization of 84 using exponents

Katyanochek1 [597]

Answer:

2^2 * 3 * 7

Step-by-step explanation:

First, divide by 2.

84 / 2 = 42

Divide by 2 again!

42 / 2 = 21

21 is divisible by 3, so divide by 3.

21 / 3 = 7

7 is prime, so we've reached the end of our little adventure!

84 = 2 * 2 * 3 * 7, or in exponents, 2^2 * 3 * 7.

Hope that helps!

8 0

4 years ago

Factor the expression x-x^2y^2

ivann1987 [24]

Factor the expression x-x^2y

5 0

3 years ago

What method would be best to use 53=4(x-3)^2-11

Veronika [31]

Answer:

x = 7 , -1

Step-by-step explanation:

SOLUTION :-

$4(x-3)^2-11 = 53$

Add 11 to both the sides.

$=> 4(x-3)^2-11+11=53+11$

$=> 4(x-3)^2 = 64$

Divide both the sides by 4.

$=> \frac{4(x-3)^2}{4} = \frac{64}{4}$

$=> (x-3)^2 = 16$

Root square both the sides.

$=> \sqrt{(x-3)^2} = \sqrt{16}$

$=> x-3 = +4 \; or -4$

Here , x will have two values -

1) $x-3 = 4$

$=> x = 4 + 3 = 7$

2) $x - 3 = -4$

$=> x = -4 + 3 = -1$

VERIFICATION :-

When x = 7 ,

$4(x-3)^2 - 11 = 4(7 - 3)^2 - 11$

$= 4 \times 4^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

When x = -1 ,

$4(x-3)^2 - 11 = 4(-1 - 3)^2 - 11$

$= 4 \times (-4)^2 - 11$

$= 4 \times 16 - 11$

$= 64 - 11$

$= 53$

7 0

3 years ago