For this case we have the following expression:
We follow the steps below:
We subtract 4x on both sides of the equation:
We subtract 10 from both sides of the equation:
Now, we must complete squares.
When we have an equation of the form:
, if we want to complete squares we must subtract c on both sides of the equation obtaining:
The square is completed by adding to both sides of the equation: 
So, we have left:
In the given expression we have:
And to complete the square we have:
Rewriting we have:
We factor the left side of the equation, that is, we look for two numbers that when added together result in -8 and when multiplied as a result 16. We have:
So, we have:
Answer:
The intermediate step is to complete squares
Answer:
The inverse will be:
Step-by-step explanation:
In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :
Now solve for y'.
First add 4 in both sides of the equation and change to the left y'.
= x + 4
Second divide by 9
/9 = (x + 4)/9
= (x + 4)/9
Now you will have to clear y, with the square root.
![[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}](https://tex.z-dn.net/?f=%5Btex%5Dy%27%5E%7B%5Cfrac%7B2%7D%7B2%7D%7D%20%3D%20%5Csqrt%7Bx%20%2B%204%7D%20%20%2F%20%5Csqrt%7B9%7D)
[/tex] =
Simplifying terms
You can check the answer by doing the evaluation of the following equation:
(f o 
) (x)
substitute the equation for y' or inverse function
f(
)
Now substitue the value into f(x)
You will have
=x
Answer:
In at least one hundred words, describe how what Markandaya reveals about Kenny helps to shape his character, and which themes in Nectar in a Sieve are developed with this information.
Step-by-step explanation:
Answer:
43-7i
Step-by-step explanation:
We are given the expression:
First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.
![\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%5B%283%20%5Ccdot%206i%29%20%2B%20%283%20%5Ccdot%207%29%20%2B%20%28%20-%204i%20%5Ccdot%206i%29%20%2B%20%28%20-%204i%20%5Ccdot%207%29%5D-%20%282%20-%203i%29%7D%20%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7B%5B18i%20%2B%2021%20%20-%2024%20%7Bi%7D%5E%7B2%7D%20%20-%2028i%5D-%20%282%20-%203i%29%7D%20)
Now combine like terms.
![\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}](https://tex.z-dn.net/?f=%20%20%5Cdisplaystyle%20%5Clarge%7B%5B%20-%2010i%2B%2021%20%20-%2024%20%7Bi%7D%5E%7B2%7D%20%5D-%20%282%20-%203i%29%7D%20)
<u>I</u><u>m</u><u>a</u><u>g</u><u>i</u><u>n</u><u>a</u><u>r</u><u>y</u><u> </u><u>U</u><u>n</u><u>i</u><u>t</u>
Therefore:-
![\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}](https://tex.z-dn.net/?f=%20%20%5Cdisplaystyle%20%5Clarge%7B%5B%20-%2010i%2B%2021%20%20-%2024%20%20%28%20-%201%29%20%5D-%20%282%20-%203i%29%7D%20%20%5C%5C%20%20%20%5Cdisplaystyle%20%5Clarge%7B%5B%20-%2010i%2B%2021%20%20%20%2B%2024%5D-%20%282%20-%203i%29%7D%20%20%5C%5C%20%20%20%5Cdisplaystyle%20%5Clarge%7B%5B%20-%2010i%2B%2045%5D-%20%282%20-%203i%29%7D%20)
Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.
Combine like terms.
Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
__
x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
_____
<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
