Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Wouldn't it just be 300 kilometers per hour as the answer?
10
A) 24 ribbons
B)1/28yards
11.u have 1/2 how?
<h2><u>Graphing</u></h2>
<h3>The graph of this function is shifted 7 units right and shifted 5 units up.</h3>
<h3>f(x) = -2/3(x - 7)² - 5</h3>
<u>Answer:</u>
<u>Explanation:</u>
- Why false? As I noticed, in the equation f(x) = -2/3(x - 7)² - 5, the vertex is (7, -5). The value of a, which is -2/3, is negative. So the graph opens downwards. The graph shifts 7 units to the right, which is correct, but graphing 5 units up is wrong. Why? 5 is negative, so it should be shifted 5 units down.
Wxndy~~
Length(l)= 2w
width(w)= w
Perimeter(P)= 2w+2l= 72 (simplify expression: divide each side by 2 )
P= w+l= 36 (plug in "2w" for "l")
P= w+(2w)= 36
P= 3w= 36 (divide each side by 3 to find the width)
w= 12 units
find length:
l=2w
l= 2(12)
l= 24 units
Answer:
The length of this rectangle is 24 units and the width is 12 units.