1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkinab [10]
3 years ago
14

For the past 40 days, Naomi has been recording the number of customers at her restaurant between 10:00 a.m. and 11:00 a.m. Durin

g that hour, there have been fewer than 20 customers on 25 out of the 40 days.
What is the experimental probability there will be **20 or more customers** on the forty-first day? Include it as fraction, decimal and percent.
Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer:

the experimental probability for 20 or more customersis 37.5%

Step-by-step explanation:

Given that

The recording of the customers would be in between 10:00 AM to 11:00 PM

In this, they have been fewer than 20 customers on 20 out of the 40 days

We need to find out the experimental probability for 20 or more customers

So,

= (40 - 25) ÷ (40)

= 15 ÷ 40

= 37.5%

Hence, the experimental probability for 20 or more customers is 37.5%

You might be interested in
I need help with multiplying polynomials using foil<br><br> Example <br> (X+5)(x-6)
MArishka [77]
Well (x+5)(×-6)
x*x =x2
x*-6=-6x
x*5 = 5x
5*-6= -30
add them all together to get x2-x-30.
I hope this is what you were asking
3 0
3 years ago
If 8=−3r+7r, then r= [blank] −−−−−−.
Svetllana [295]

Answer:

r = 2

Step-by-step explanation:

8 =  - 3r + 7r \\ 8 = 4r \\ 4r = 8  \\ \\ r =  \frac{8}{4}  \\  \\ r = 2

8 0
3 years ago
Hey! i’ll give brainliest please help!
Bogdan [553]

Answer:

Building of an army

Step-by-step explanation:

6 0
3 years ago
Two teams A and B play a series of games until one team wins three games. We assume that the games are played independently and
Olenka [21]

Answer:

The probability that the series lasts exactly four games is 3p(1-p)(p^{2} + (1 - p)^{2})

Step-by-step explanation:

For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

We also need to know a small concept of independent events.

Independent events:

If two events, A and B, are independent, we have that:

P(A \cap B) = P(A)*P(B)

What is the probability that the series lasts exactly four games?

This happens if A wins in 4 games of B wins in 4 games.

Probability of A winning in exactly four games:

In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:

Event A: A wins two of the first three games.

Event B: A wins the fourth game.

P(A):

A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(A) = P(X = 2) = C_{3,2}.p^{2}.(1-p)^{1} = 3p^{2}(1-p)

P(B):

The probability that A wins any game is p, so P(B) = p.

Probability that A wins in 4:

A and B are independent, so:

P(A4) = P(A)*P(B) = 3p^{2}(1-p)*p = 3p^{3}(1-p)

Probability of B winning in exactly four games:

In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So

Event A: A wins one of the first three.

Event B: B wins the fourth game.

P(A)

P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(A) = P(X = 1) = C_{3,1}.p^{1}.(1-p)^{2} = 3p(1-p)^{2}

P(B)

B wins each game with probability 1 - p, do P(B) = 1 - p.

Probability that B wins in 4:

A and B are independent, so:

P(B4) = P(A)*P(B) = 3p(1-p)^{2}*(1-p) = 3p(1-p)^{3}

Probability that the series lasts exactly four games:

p = P(A4) + P(B4) = 3p^{3}(1-p) + 3p(1-p)^{3} = 3p(1-p)(p^{2} + (1 - p)^{2})

The probability that the series lasts exactly four games is 3p(1-p)(p^{2} + (1 - p)^{2})

8 0
3 years ago
Which of the following are solutions to the quadratic equation? Check all that
Reil [10]

Answer:

x=-9/10

Step-by-step explanation:

2x+8x+16=7

Step 1: Simplify both sides of the equation.

2x+8x+16=7

(2x+8x)+(16)=7(Combine Like Terms)

10x+16=7

10x+16=7

Step 2: Subtract 16 from both sides.

10x+16−16=7−16

10x=−9

Step 3: Divide both sides by 10.

10x/10

=

−9/10

x=-9/10

7 0
3 years ago
Read 2 more answers
Other questions:
  • For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term
    5·1 answer
  • Erin made 12 pints of juice. She drinks 3 cups of juice each day. How many days will Erin take to drink all of the juice she mad
    10·1 answer
  • Help again 14 more questions
    15·1 answer
  • HELP AGANI PLZ
    13·1 answer
  • Help please, 100 points
    14·2 answers
  • I WILL MARK YOU BRAINLIEST IF YOU ANSWER
    6·2 answers
  • - (64 - 36 + 5) + (45 - 87) = ?
    15·1 answer
  • HELP!: HELP!: HELP!:
    10·2 answers
  • In the triangles below, mzB = m2P and mZT = MZJ.
    10·1 answer
  • Find the radius. Round to the nearest tenth.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!