A car passes a landmark on a highway traveling at a constant rate of 45 kilometers per hour.
Let t be the time taken by second car
So t+1 is the time taken by first car
Distance = speed * time
Distance traveled by first car = 45 * (t+1)
second car passes the same landmark traveling in the same direction at 65 kilometers per hour
Distance traveled by second car = 65 * (t)
When second car overtakes the first car then their distance are same
65 t = 45(t+1)
65t = 45t + 45
Subtract 45 t from both sides
20t = 45
Divide both sides by 20
so
It took 2.25 hours for the second car to overtake first car
Answer:
y=-1x+8
Step-by-step explanation:
idk what to do here
Answer:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
I think it would would be 42g.
Answer: x=10
Step-by-step explanation: