(2, - 9),(- 1, 4)=<br><br> Plssss helppp me rnnn

Todd earned some money doing chores. He spent one-fourth of his money see a movie. Then he spent $6.00 on popcorn and drinks. Wh

Vsevolod [243]

Answer: Todd earned $40 mowing the neighbor's lawn.

Step-by-step explanation:

Let x represent the amount of money that Todd earned, mowing his neighbor's lawn.

He spent one-fourth of his money see a movie. It means that the amount spent in seeing a movie is x/4

Then he spent $6.00 on popcorn and drinks. It means that the total amount spent is

x/4 + 6

The amount left would be

x - (x/4 + 6) = x - x/4 - 6

When he went home, he had $24.00 left. It means that

x - x/4 - 6 = 24

x - x/4 = 24 + 6

x - x/4 = 30

Cross multiplying by 4, it becomes

4x - x = 120

3x = 120

x = 120/3

x = $40

7 0

3 years ago

The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b

Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

b) $p_v =P(z>2.32)=0.0102$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

For this case the statistic is given by $z_{calc}= 2.32$

Part b: Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.32)=0.0102$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0

3 years ago

37 degrees Celsius to Fahrenheit

konstantin123 [22]

98.6 degrees fahrenheit

5 0

3 years ago

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HELP TIMED BRAINLIST

lesya692 [45]

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it's D