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shutvik [7]
3 years ago
10

A manufacturer with exclusive rights to a sophisticated new industrial machine is planning to sell a limited number of the machi

nes to both foreign and domestic firms. It is estimated that if the manufacturer supplies machines to the domestic market and machines to the foreign market, the machines will sell for −+ thousand dollars apiece domestically, and for +− thousand dollars apiece abroad. If the manufacturer can produce the machines at the cost of $ apiece, how many should be supplied to each market to generate the largest possible profit?
Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

Supply all machines to the which ever market provides the highest price.

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4/9x + 1/5x =58 need help solving this
iogann1982 [59]

Answer:

x=90

Step-by-step explanation:

First, it would help to make it so that the x's are not next to fractions. To do this, you can multiply all terms in the equation by 45. 45 is the closest common factor of 9 and 5, the denominators of the fractions. The answer would be;

20x+9x=2610

Then solve.

29x=2610

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6 0
3 years ago
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dedylja [7]

Answer:

No.

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3 years ago
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jekas [21]
(a) (i)  In first 4 minutes Mary's speed was 600 / 4 = 150 m / minute
     (ii)  in last 4 minutes her speed was (1000-600) / 4 = 400/4 = 100 m/min
(b) Marys average speed for the whole journey = 1000/8  = 125 m/min
(c) 200 m
(d) Peter arrived at school after 7 minutes . Mary took 8 minutes. Peter first.
(e) Where they met is given by where the 2  curves  intersect. That is at time 6.8 minutes and 880 m from Mary's home
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3 0
3 years ago
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A school P is 16km due west of a school Q. what is the bearing of Q from P​
Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find  the bearing of Q from P​

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of QP------------------>Q

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of  School Q from P is 16Km due east of school P

7 0
3 years ago
What is the solution of log2x+3125 = 3? (1 point)
enot [183]

Answer:

x =  - 1062.5

Step-by-step explanation:

Assuming the equation is:

log(2x + 3125)  = 3

Then taking antilogarithms gives:

2x + 3125 =  {10}^{3}

We simplify on the left to get:

2x + 3125 = 10 \times 10 \times 10

This gives us:

2x + 3125 =1000

We subtract 3125 from both sides to get:

2x = 1000 - 3125

2x = -  2125

x =  - 1062.5

6 0
3 years ago
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