45 should be the answer for that specific question.
Your answer would be Quadrant III (Answer #3)
So to solve for r, you need to isolate the variable onto 1 side. To do that, divide both sides by 2 pi, and your answer will be 
The ordered pairs ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4 ) , ( 4 , 2 5 6 ) , ( 5 , 1 , 0 2 4 ) ( 1 , 4 ) , ( 2 , 1 6 ) , ( 3 , 6 4
Annette [7]
Answer:
The rule is f(x) = 2^(2x).
Step-by-step explanation:
Note that 4 = 2^2, 16 = 4^2, 64 = 8^2, 256 = 16^2 and 1024 = 32^2
and the first numbers in the ordered pairs are 1 , 2 ,3, 4, 5
compare this with 2, 4 , 8, 16 , 32.
We see that the rule for this is 2^x where x is the sequence number.
So the rule for the original ordered pairs is (2^x)^2.
= 2^2x.
<u>Answer:</u>
The probability of rolling an even number and then an odd number is
Option C is correct
<u>Solution:</u>
Given, You roll a six-sided die twice.
We have to find what is the probability of rolling an even number and then an odd number?
We know that, rolling single die two times is equivalent to two dice rolling at a time.

So, now, total possible outcomes = 6 x 6 = 36
And, number of favourable outcomes = 3 even on 1st die x 3 odd on 2nd die = 3 x 3 = 9
Then, probability = 
Hence, the probability of given condition is
and option c is correct.