IQR=36-16.. which would give you 20!
Answer:
x = 22
Step-by-step explanation:
I interpreted your problem as:

I simplified the problem to:

I combined like terms:

I moved all x to one side and all other constants to the other:

I divided by 3/2 (1.5) on both sides to isolate x:

Hope it helps! (:
Answer:
-1
Step-by-step explanation:
m = -7 / 7 = -1 / 1 = -1
Answer:
Step-by-step explanation:
Given that angle A is in IV quadrant
So A/2 would be in II quadrant.
sin A = -1/3
cos A = 
(cos A is positive since in IV quadrant)
Using this we can find cos A/2
