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Anettt [7]
2 years ago
10

Help I need help pls pls

Mathematics
1 answer:
katen-ka-za [31]2 years ago
7 0

Answer:

  see attached

Step-by-step explanation:

The boundary lines are drawn by considering the relation as an equation.

The first "equation" describes a line with slope -8/3 through the y-intercept point (0, 6). Another point on that line would be 8 units down and 3 units right of (0, 6), at (3, -2). Both inequalities include the "or equal to" case, so both boundary lines are solid lines.

Since we have y ≥ ( ), the shading is above the line.

__

The second "equation" describes a line with a slope of 5/3 through the y-intercept point (0, -7). Another point would be 5 units up and 3 units right of (0, -7), at (3, -2). Since we have y ≤ ( ), the shading is below the line.

That is, the solution region is in the right-hand quadrant of the X where the lines cross. It includes the lines themselves.

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The graphs of ​ f(x)=2x+4 ​ and ​ g(x)=10−4x ​ intersect at (1, 6) . What is the solution of the equation 2x+4=10−4x ?
Gnoma [55]

Answer:

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Step-by-step explanation:

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