Let us consider point A,
We are given that,
Now, we can simply put the given values at Point A,
To verify, let's move on to next point, i.e. point B,
Hence, verified, the constant is 
.
Hope it helps you :)
Answer:
51
Step-by-step explanation:
when n=1
<h2><u><em>t 1=1 </em></u></h2>
<u><em>when n=2</em></u>
<u><em>t2=4</em></u>
<u><em>as first term is 1 and second term is 4 so the common difference is 3 ,for 6 term if you put this in formula for sum to the n term you will get 51 </em></u>
<u><em>t1 =1</em></u>
<u><em>d=3</em></u>
<u><em>n=6 </em></u>
<u><em>than S6=51 </em></u>
Answer
what you need help with my man
Step-by-step explanation:
Answer: the maximum is 25.
Step-by-step explanation: a max/min can occur on the endpoints of a function and critical points of the function's derivative.
f(x)=x^4-x^2+13
f'(x)=4x^3-2x
The critical points of f'(x) occur when f'(x) is zero or undefined. f'(x) is not ever undefined in this case, so we just need to find the x values for when it's zero.
0=4x^3-2x
x=.707, -.707
Now that we have the critical points of f'(x) (.707 and -.707) and endpoints (-1 and 2), we can plug in these x values into the original function to determine its maximum. When you do this you'll find that the greatest y value produced occurs when x=2 and results in a max of 25.
