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salantis [7]
3 years ago
8

Which is the graph of f(x)=3 two thirds to the power of x

Mathematics
1 answer:
labwork [276]3 years ago
7 0
It looks similar to
y
=
x
1
3
=
3
√
x
.
Here is the graph of
y
=
x
1
3
=
3
√
x
.
graph{y = x^(1/3) [-3.08, 3.08, -1.538, 1.54]}
You can scroll in and out and drag the graph window around using a mouse.
The difference is that the function in this question has squared all of the
3
r
d
roots, so all of the
y
values are positive (and have the value of the square.)
x
2
3
=
(
x
1
3
)
=
(
3
√
x
)
2

Here is the graph of
f
(
x
)
=
x
2
3

graph{y = x^(2/3) [-3.08, 3.08, -1.538, 1.54]}
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Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
Kelso sold digital cameras on her website. She bought the cameras for $65 each and included 60% markup to get the selling price.
Butoxors [25]
Find 60% of 65 then add it to 65

0.6 x 65 = 39

now add it to 65:

39 + 65 = 104

They are selling them for 104$
 
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Cheryl drove 4 hours at a constant rate to travel 160 miles. At what rate did she drive?
suter [353]
40 miles per hour

160/4=40
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Answer: 2 quarts 3 cups

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