If you would like to find a step that can be used to find the solution to the set of equations, you can do this using the following steps:
c = 2d + 1
c = 3d + 5
__________
c = c
2d + 1 = 3d + 5
2d - 3d = 5 - 1
- d = 4
d = -4
The correct result would be <span>2d + 1 = 3d + 5.</span>
Answer: as a number?
Step-by-step explanation:
Be a little more specific
Answer:
24 or 29 more numbers
Step-by-step explanation:
Answer:
P(X>17) = 0.979
Step-by-step explanation:
Probability that a camera is defective, p = 3% = 3/100 = 0.03
20 cameras were randomly selected.i.e sample size, n = 20
Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97
Probability that more than 17 cameras are working P ( X > 17)
This is a binomial distribution P(X = r)
P(X>17) = P(X=18) + P(X=19) + P(X=20)
P(X=18) =
P(X=18) =
P(X=18) = 0.0988
P(X=19) =
P(X=19) =
P(X=19) = 0.3364
P(X=20) =
P(X=20) =
P(X=20) = 0.5438
P(X>17) = 0.0988 + 0.3364 + 0.5438
P(X>17) = 0.979
The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch
Answer:
a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.
b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.
Step-by-step explanation:
In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:
For n=25 we have:
The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.
This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.
If n=50, we have: