All categories

3 years ago

I NEED HELP ASAP PLEASE

Mathematics

2 answers:

BaLLatris [955]3 years ago

8 0

The answer is A, 63 degrees, because when two angles complement each other they add up to 90 degrees. 63 + 27 = 90.

Vika [28.1K]3 years ago

8 0

the answer is a 26 degrees

You might be interested in

The elevation of a mountain is 27,370 feet. Due to erosion, this mountain is reduced by 0.2% each year. In how many years will t

koban [17]

Answer:

7 years

Step-by-step explanation:

27370 - 26986.82 = 383.18ft

0.2% = 0.2/100 = 0.002

27370*0.002 = 54.74

each year the montain reduce your elevation

54.74ft

then:

383.18/54.74 = 7

Answer:

7 years

4 0

3 years ago

If a = 3 and b = 5, what is the value of a+. 62? 9 + 25 84 6 + 10 82

Harman [31]

Answer:

a+62=65

Step-by-step explanation:

if a=3 then 62+3=65

4 0

3 years ago

How would I solve 16x^4-41x^2+25=0 ???

sveticcg [70]

$16{ x }^{ 4 }-41{ x }^{ 2 }+25=0$

${ x }^{ 4 }={ ({ x }^{ 2 }) }^{ 2 }\\ \\ 16{ ({ x }^{ 2 }) }^{ 2 }-41{ x }^{ 2 }+25=0$

First of all to make our equation simpler, we'll equal $x^{2}$ to a variable like 'a'.

So,

${ x }^{ 2 }=a$

Now let's plug $x^{2}$ 's value (a) into the equation.

$16{ ({ x }^{ 2 }) }^{ 2 }-41{ x }^{ 2 }+25=0\\ \\ { x }^{ 2 }=a\\ \\ 16{ (a) }^{ 2 }-41{ a }+25=0$

Now we turned our equation into a quadratic equation.

(The variable 'a' will have a solution set of two solutions, but 'x' , which is the variable of our first equation will have a solution set of four solutions since it is a quartic equation (fourth-degree equation) )

Let's solve for a.

The formula used to solve quadratic equations ;

$\frac { -b\pm \sqrt { { b }^{ 2 }-4\cdot t\cdot c } }{ 2\cdot t }$

The formula is used in an equation formed like this :

$t{ x }^{ 2 }+bx+c=0$

In our equation,

t=16 , b=-41 and c=25

Let's plug the values in the formula to solve.

$t=16\quad b=-41\quad c=25\\ \\ \frac { -(-41)\pm \sqrt { -(41)^{ 2 }-4\cdot 16\cdot 25 } }{ 2\cdot 16 } \\ \\ \frac { 41\pm \sqrt { 1681-1600 } }{ 32 } \\ \\ \frac { 41\pm \sqrt { 81 } }{ 32 } \\ \\ \frac { 41\pm 9 }{ 32 }$

So the solution set :

$\frac { 41+9 }{ 32 } =\frac { 50 }{ 32 } \\ \\ \frac { 41-9 }{ 32 } =\frac { 32 }{ 32 } =1\\ \\ a\quad =\quad \left\{ \frac { 50 }{ 32 } ,\quad 1 \right\}$

We found a's value.

Remember,

${ x }^{ 2 }=a$

So after we found a's solution set, that means.

${ x }^{ 2 }=\frac { 50 }{ 32 }$

and

${ x }^{ 2 }=1$

We'll also solve this equations to find x's solution set :)

${ x }^{ 2 }=\frac { 50 }{ 32 } \\ \\ \frac { 50 }{ 32 } =\frac { 25 }{ 16 } \\ \\ { x }^{ 2 }=\frac { 25 }{ 16 } \\ \\ \sqrt { { x }^{ 2 } } =\sqrt { \frac { 25 }{ 16 } } \\ \\ x=\quad \pm \frac { 5 }{ 4 }$

${ x }^{ 2 }=1\\ \\ \sqrt { { x }^{ 2 } } =\sqrt { 1 } \\ \\ x=\quad \pm 1$

So the values x has are :

$\frac { 5 }{ 4 }$ , $-\frac { 5 }{ 4 }$ , $1$ and $-1$

Solution set :

$x=\quad \left\{ \frac { 5 }{ 4 } \quad ,\quad -\frac { 5 }{ 4 } \quad ,\quad 1\quad ,\quad -1 \right\}$

I hope this was clear enough. If not please ask :)

3 0

3 years ago

Read 2 more answers

Find the train angle of 12yd 16yd

denis-greek [22]

I think the answer is 28yd

7 0

3 years ago

Find the missing side length XI. round your answer to the nearest tenth.

lianna [129]

Answer: XI = 10.35 mm

Step-by-step explanation:

Considering the given triangle XIF, to determine XI, we would apply the sine rule. It is expressed as

a/SinA = b/SinB = c/SinC

Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes

XI/SinF = XF/SinI = FI/SinX

The sum of the angles in a triangle is 180°. It means that

F + 63 + 52 = 180

F = 180 - (63 + 52)

F = 65°

Therefore

XI/Sin 65 = 9/Sin 52

Cross multiplying, it becomes

XISin52 = 9Sin65

0.788XI = 9 × 0.906

0.788XI = 8.154

XI = 8.154/0.788

XI = 10.35

7 0

3 years ago