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natulia [17]
3 years ago
12

Please, help I don’t understand what im supposed to do.

Mathematics
1 answer:
Blizzard [7]3 years ago
3 0

Answer:

16,800 votes.

Step-by-step explanation:

In the singing competition 42,000 votes were counted.

The winner received 3/5 of the votes.

The part of the votes that the winner did not receive was 1 - 3/5 = 2/5

So the winner did not receive 2/5 of 42,000 votes which is equivalent to:

\frac{2(42,000)}{5} = 16,800 votes.


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What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?
german
For this case we have the following function:
 f(x) =  tan(\frac{x^2}{9})
 The average rate of change is given by:
 AVR =  \frac{f(x2) - f(x1)}{x2- x1}
 Evaluating the function for the given interval we have:
 For x = 1.25:
 f(1.25) = tan(\frac{1.25^2}{9})
 f(1.25) = 0.18
 For x = 2:
 f(2) = tan(\frac{2^2}{9})
 f(2) = 0.48
 Then, replacing values we have:
 AVR = \frac{0.48 - 0.18}{2 - 1.25}
 AVR = 0.4
 Answer:
 
the average value of on the closed interval [1.25, 2] is:
 
AVR = 0.4



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Answer:

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A cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shif
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We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is \frac{7\pi}{12}. The graph of the function does not show a phase shift. We are asked to write the equation of our function.

We know that general form a cosine function is y=A\cos(b(x-c))-d, where,

A = Amplitude,

\frac{2\pi}{b} = Period,

c = Horizontal shift,

d = Vertical shift.    

The equation of parent cosine function is y=\cos(x). Since function is reflected about x-axis, so our function will be y=-\cos(x).

Let us find the value of b.

\frac{2\pi}{b}=\frac{7\pi}{12}

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f(x)=-11\cos(\frac{24}{7}x)-9

Therefore, our required function would be f(x)=-11\cos(\frac{24}{7}x)-9.

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