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lakkis [162]
3 years ago
8

A girl has 5 more than twice as many pennies as she has dimes. Altogether she has

Mathematics
1 answer:
Cloud [144]3 years ago
7 0

Answer:

80 total coins

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A real estate agent earns a 6% commission on each property she sells. If she sells a detached house for $200,000 and a cottage f
xz_007 [3.2K]
I think d is the answer
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25 ≡ x mod 5 <br><br> not sure how to solve this pls
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X= 5/mod I think this is the answer
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3 years ago
Justin ate 1/4 of a pie. If there were 8 slices of pie, how many sclices did justin eat
WITCHER [35]

Answer:

2

Step-by-step explanation:

8 x 1/4 = 2

He ate 2 slices

5 0
2 years ago
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Pleas answer this fast <br><br> i dont under stand
Lorico [155]

Answer:

196ft^2

Step-by-step explanation:

direct the diagram as shown in my image attachment

A = 1/2 x (18-(9-7)) x (6+8) = 112ft^2

B = 2 x (6+8) = 28ft^2

C = 7 x 8 = 56ft^2

total area = 112 + 28 + 56 = 196ft^2

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3 years ago
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The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =
pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

so that

v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du

\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is s(0)=0\,\mathrm m. Then its displacement over the time interval [0, 3] is

s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}

c) The total distance traveled is the integral of the absolute value of the velocity function:

s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt

v(t) for 0\le t and v(t)\ge0 for \cos^{-1}\left(-\frac29\right)\le t\le3, so we split the integral into two as

\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt

=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt

\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}

4 0
3 years ago
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