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2 years ago

6

Can anyone pls help me in dis

1 answer:

nikklg [1K]2 years ago

7 0

Answer:

10.6 cm to the nearest tenth.

Step-by-step explanation:

If we let one side = x. So as each side of a square are equal, and using Pythagoras we have:

x^2 + x^2 = 15^2

2x^2 = 225

x^2 = 112.5

x = √112.5

x = 10.61.

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Find the expected value and the variance of the number of times one must throw a die until the outcome 1 has occurred 5 times.

Kazeer [188]

Answer: E(X) = 30; Var[X] = 180

Step-by-step explanation: This is a <u>Bernoulli</u> <u>Experiment</u>, i.e., the experiment is repeated a fixed number of times, the trials are independents, the only two outcomes are "success" or "failure" and the probability of success remains the same, So, to calculate <em><u>Expected</u></em> <em><u>Value</u></em>, which is the mean, in these conditions:

$E(X)=\frac{r}{p}$

r is number of times it is repeated

p is probability it happens

Solving:

$E(X)=\frac{5}{1/6}$

E(X) = 30

<u>Variance</u> is given by:

$Var[X]=\frac{r(1-p)}{p^{2}}$

$Var[X]=\frac{5(1-1/6)}{(1/6)^{2}}$

$Var[X]=5.\frac{5}{6}.6^{2}$

Var[X] = 180

Expected Value and Variance of the number of times one must throw a die until 1 happens 5 times are 30 and 180, respectively.

4 0

2 years ago

Ships A and B are 1,425 feet apart and detect a submarine below them. The angle of depression from ship A to the submarine is 59

andreyandreev [35.5K]

Answer: The distance from ship B to the submarine is 1270.68 feet and the distance from ship A to the submarine is 1084.18 feet.

Step-by-step explanation:

Since we have given that

Distance between Ships A and B = 1425 feet

Angle of depression from ship A to the submarine =59°

Angle of depression from ship B to the submarine = 47°

As shown in the figure below:

Remaining angle will be

$180\textdegree-(47\textdegree+59\textdegree)\\\\=180\textdegree-106\textdegree\\\\=74\textdegree$

So, we will use "Sine formula ":

$\frac{\sin 74\textdegree}{1425}=\frac{\sin 59\textdegree}{B}\\\\B=\frac{1425\times \sin 59\textdegree}{\sin 74\textdegree}\\\\B=1270.68\ feet$

Similarly,

$\frac{\sin 74\textdegree}{1425}=\frac{\sin 47\textdegree}{A}\\\\A=\frac{1425\times \sin 47\textdegree}{\sin 74\textdegree}\\\\A=1084.18\ feet$

Hence, the distance from ship B to the submarine is 1270.68 feet and the distance from ship A to the submarine is 1084.18 feet.

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2 years ago

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Vikki [24]

Answer:

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Step-by-step explanation:

2+3+5

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2 years ago

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

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3 ⩽ x + 5

-2 ⩽ x

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