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4 years ago

Can anyone pls help me in dis

Mathematics

1 answer:

nikklg [1K]4 years ago

7 0

Answer:

10.6 cm to the nearest tenth.

Step-by-step explanation:

If we let one side = x. So as each side of a square are equal, and using Pythagoras we have:

x^2 + x^2 = 15^2

2x^2 = 225

x^2 = 112.5

x = √112.5

x = 10.61.

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Alex has a bag of marbles. Each marble is red, blue, or yellow , and the ratio of the red to blue to yellow marbles is 6:10:15.

lesantik [10]

Answer:

There are 150 blue marbles in Alex's bag.

Step-by-step explanation:

Let $x$ , $y$ , $z$ be the quantities of red, blue and yellow marbles, respectively. From statement we derive three rational equations for initial and final ratios:

Initial ratio

$\frac{x}{y} = \frac{6}{10}$ (1)

$\frac{y}{z} = \frac{10}{15}$ (2)

Final ratio

$\frac{x + 10}{z - 25} = \frac{1}{2}$ (3)

After some algebraic handling we get the following system of linear equations:

$x - \frac{3}{5}\cdot y = 0$ (1)

$y - \frac{2}{3}\cdot z = 0$ (2)

$2\cdot (x + 10) = z - 25$

$2\cdot x +20 = z - 25$

$2\cdot x - z = -45$ (3)

The solution of the system of linear equations is:

$x = 90$ , $y = 150$ , $z = 225$

There are 150 blue marbles in Alex's bag.

5 0

3 years ago

What is 5(x+10)+x =

zhuklara [117]

Answer:

6x+50

Step-by-step explanation:

5(x+10)+x=5x+50+x=6x+50

3 0

3 years ago

Sarah’s neighbor offers to pay her $5 for every shark tooth she finds on the beach. After collecting only three shark’s teeth, S

Vaselesa [24]

Answer:

=15j+15

Step-by-step explanation:

4 0

3 years ago

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A juice machine is set to dispense 16 ounces of juice. The amount of juice

enyata [817]

Answer:

C. 15.40 ounces to 16.90 ounces

Step-by-step explanation:

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3 years ago

What is the domain and range of the square root of x+3-1?

Nata [24]

Answer:

$\large\boxed{\text{The domain:}\ x\geq-3\to x\in[-3,\ \infty)}\\\boxed{\text{The range:}\ y\geq-1\to y\in[-1,\ \infty)}$

Step-by-step explanation:

$y=\sqrt{x+3}-1\\\\The\ domain:\\\\x+3\geq0\qquad\text{subtract 3 from both sides}\\\\x\geq-3\to x\in[-3,\ \infty)\\\\The\ range:\\\\\sqrt{x+3}\geq0\qquad\text{subtract 1 from both sides}\\\\\sqrt{x+3}-1\geq-1\\\\y\geq-1\to y\in[-1,\ \infty)$

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3 years ago