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sweet-ann [11.9K]
3 years ago
10

You deposit $260 every six months into an account earning 4.1% interest compounded semiannually.

Mathematics
1 answer:
butalik [34]3 years ago
8 0

Answer:

ITS B ..

Step-by-step explanIation:

subs to sir joel his playing blockman go

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Quadrilateral ABCD has coordinates A (3,1) B (4,4) C (7,5) D (6,2). Quadrilateral ABCD is a ?
ASHA 777 [7]
The Quadrilateral ABCD with coordinates (3, 1), (4, 4), (7, 5), (6, 2) is a rhombus because its length and width are both square root of 10 units and adjacent sides are not perpendicular. This can be seen by plotting the points you can either plot it or by using programs.

I hope this helps, God bless, and have a great day!
Brainliest is always appreciated :)
3 0
3 years ago
Read 2 more answers
Combine the like terms to create an equivalent expression: <br><br>−4p+(−6p)
Y_Kistochka [10]

THE ANSWER IS -10P.

Step-by-step explanation:

USING BY MULTIPLICATION RULE.

minus × plus = minus

then minus × minus = plus.

so we add the 4p+6p= -10p.

why -10p is come it means THE BIGGER NUMBER SIGN IS MINUS. So it's comes -10p.

<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
How many 1/2 are there in 7 1/2 ?
My name is Ann [436]

Answer:

There are 15 halves in 7 1/2.

4 0
3 years ago
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Verify whether the indicated numbers are zeroes of their corresponding polynomials.
aleksley [76]

Answer:

  • No, incorrect

Step-by-step explanation:

<u>Given</u>

  • Q(s) = -4s^3 + 7s^2 - 24;
  • s = -4 and 1

<u>Verifying zeroes</u>

Q(-4) =

  • -4(-4)^3 + 7(-4)^2 - 24 =
  • 256 + 112 - 24 =
  • 344
  • Incorrect as 344 ≠ 0

Q(1) =

  • -4(1)^3 + 7(1)^2 - 24 =
  • -12 + 7 - 24 =
  • -29
  • Incorrect as -29 ≠ 0

3 0
3 years ago
List any restrictions on the domain for the equation <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2B9%7D%7Bx%2B2%7D%20" id="
frez [133]
For a fraction, if the denominator turns to 0, the fraction becomes undefined, and therefore, that's a restriction on a rational.

now, what values of "x" makes the denominator 0?  let's check,

x+2 = 0

x = -2

so, if "x" ever becomes -2, then you'd get

\bf \cfrac{x+9}{x+2}\implies \cfrac{x+9}{-2+2}\implies \implies \cfrac{-2+9}{-2+2}\implies \stackrel{und efined}{\cfrac{7}{0}}

so, the domain, or values "x" can take on safely, are any real numbers EXCEPT -2.
7 0
4 years ago
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