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Scorpion4ik [409]
3 years ago
15

Which of these expressions are equivalent to the expression below. CHOOSE 2. *

Mathematics
1 answer:
leonid [27]3 years ago
8 0
Cappp u love me and I love h to sorry I hate u
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Solve the system of equations.<br> 7x+10y=36<br> y=2x+9<br><br> x = ______<br><br> y = ______
wel

Step-by-step explanation:

Substitute the y in the 1st equation with the 2nd equation.

7x + 10(2x + 9) = 36

7x + 20x + 90 = 36

27x + 90 = 36

3x + 10 = 4

3x = -6

x = -2

So now we can find y.

y = 2x + 9 = 2(-2) + 9 = (-4) + 9 = 5.

So x = -2, y = 5.

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3 years ago
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How long will it take a seal swimming at a speed of 8 miles per hour to travel 52 miles
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3 years ago
trevor bought a large container of 36 pretzel snack bags for $14.04 what is the cost of each snack bag
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Answer:

$0.39

Step-by-step explanation:

You divide 36 and $14.04 to get the answer, which is $0.39.

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3 years ago
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The teller show committee sold a total of 5030 tickets in advance. Student tickets cost $3 each and the adult tickets cost $4 ea
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Answer:it’s b..........

Step-by-step explanation:

4 0
3 years ago
A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
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