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3 years ago

15

Which of the following best approximates the line of best fit ?

2 answers:

sergiy2304 [10]3 years ago

5 0

Answer: the answer is A because it is the line of best fit and has more dots on it therefore my answer is valid i know this because i learned it in school

Kamila [148]3 years ago

4 0

Answer:

A

Step-by-step explanation:

a as it gives the best fit

b is too high

c is too low

d is just bad

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A ladder is placed against a building so that it reaches 35 feet up the side of the building when its base is 12 feet from the b

tatyana61 [14]

Answer:

35 multiplied by 12

Step-by-step explanation:

Because either you multiply it or you do sohcahtoa

3 0

3 years ago

A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year

Roman55 [17]

Answer:

The required equation is $y = 18(1.15)^x$ .

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

$y = 18(1.15)^x$

Now verify this by substituting x=1 in above equation.

$y = 18(1.15)^1=20.7$

Which is true.

Hence, the required equation is $y = 18(1.15)^x$ .

7 0

3 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Please please help me

Anarel [89]

so you are going to use the Pythagorean theorem on the smaller triangle to find the connecting side's length

${5}^{2} = {3}^{2} ( {b}^{2} ) \\ b = 4$

now you can find the bigger triangle's hypotenuse

${6}^{2} + {4}^{2} = {c}^{2} \\$

c=4

8 0

3 years ago

How do you factor 5x^2b^2 + 14xb^2 -3b^2

Monica [59]

Answer:

$5b^2(x-0.2)(x+3)$

Step-by-step explanation:

The first thing that I noticed was that all of the terms had a common factor of $b^2$ . You can therefore factor that out first:

$5x^2b^2 + 14xb^2 -3b^2= \\\\b^2(5x^2+14x-3)$

Now, you have a quadratic equation inside the parentheses. Factoring, you find that the roots are -0.2 and 3, meaning that you can further factor this expression to be:

$5b^2(x-0.2)(x+3)$

Hope this helps!

3 0

3 years ago