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Mariana [72]
2 years ago
11

The series 6 + 6 + 6+ 6 + 6 +

Mathematics
2 answers:
HACTEHA [7]2 years ago
8 0

Answer:

23

Step-by-step explanation:

Alexandra [31]2 years ago
6 0
Do you mean 6 to the 5th power. or is there another 6, if so then it would be 6 to the 6th power.
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For what value of a does (1/7)^3a+3=343^a-1
NemiM [27]

Answer:

a=0

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5 0
2 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
2 years ago
PLEASE HELP AND EXPLAIN THIS ALSO GRAPH PLS<br> the answer choices are -6, -4, 6, 4
liubo4ka [24]

\sf \: (x,y) = (  - 4, - 6)

\rule{300pt}{3pt}

  • <em>Detailed</em><em> </em><em>solution</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>found</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>attachment</em><em>!</em><em>!</em><em>~</em>

4 0
2 years ago
A 20-gallon container is filled halfway with a mixture that is $90\%$ vinegar and $10\%$ water. How many gallons of water must b
Yuki888 [10]

Answer:

5 gallons of water must be added.

10 gallons to start with

adding 'x' gallons of water      final volume = 10 + x

.9 (10) = amount of vinegar

.1(10) = amount of water

amount of vinegar before and after water addition is constant

.9(10) = .6(10+x)  

9 = 6 + .6x

3 = .6x

x = 5 gallons of water to be added

(i truly hope i helped you

8 0
2 years ago
Functions<br> F(1) if f(x)=x+3
ratelena [41]

Answer:

the ewser is 4

Step-by-step explanation:

sence x=1 1+3 =4

5 0
2 years ago
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