2 years ago

The series 6 + 6 + 6+ 6 + 6 +

Mathematics

2 answers:

HACTEHA [7]2 years ago

8 0

Answer:

Step-by-step explanation:

Alexandra [31]2 years ago

6 0

Do you mean 6 to the 5th power. or is there another 6, if so then it would be 6 to the 6th power.

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Use benchmark fractions to compare 2/9 and 5/6. Part A Which of the following is a benchmark fraction Heather can use to compare

Dimas [21]

Answer:

Step-by-step explanation:

2/9 and 5/6 have a lcm of 30.

5 0

2 years ago

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Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

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2 years ago

Pls help; tysmmmmmmn <3

Alexxx [7]

8 is the answer, yw have a nice day:)

3 0

3 years ago

Read 2 more answers

HELP ASAP!!!!!

Sergeu [11.5K]

Answer: Y= - 1/2x - 8
If you move y to one side by itself that’s what you’ll get and you can check this answer by multiplying each side by 2 and moving the x ti the left side and you’ll get your beginning equation

If it not right feel free to comment and tell me

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2 years ago

Need help with number 12 n 13 Asap

Arlecino [84]

Step-by-step explanation:

it's explained in the solution

7 0

3 years ago