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Mekhanik [1.2K]

2 years ago

9

As part of the quality-control program for a catalyst manufacturing line, the raw materials (alumina and a binder) are tested fo

r purity. The process requires that the purity of the alumina be greater than 84%. A random sample from a recent shipment of alumina yielded the following results (in percent):
93.2, 87.0, 92.1, 90.1, 87.1, and 93.4.
A hypothesis test will be done to determine whether or not to accept the shipment.
a. State the appropriate null and alternate hypotheses.
b. Compute the P-value.
c. Should the shipment be accepted? Explain.

1 answer:

denis-greek [22]2 years ago

6 0

Hi how was your day today Mr. person

You might be interested in

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Otrada [13]

I guess the "5" is supposed to represent the integral sign?

$I=\displaystyle\int_1^4\ln t\,\mathrm dt$

With $n=10$ subintervals, we split up the domain of integration as

[1, 13/10], [13/10, 8/5], [8/5, 19/10], ... , [37/10, 4]

For each rule, it will help to have a sequence that determines the end points of each subinterval. This is easily, since they form arithmetic sequences. Left endpoints are generated according to

$\ell_i=1+\dfrac{3(i-1)}{10}$

and right endpoints are given by

$r_i=1+\dfrac{3i}{10}$

where $1\le i\le10$ .

a. For the trapezoidal rule, we approximate the area under the curve over each subinterval with the area of a trapezoid with "height" equal to the length of each subinterval, $\dfrac{4-1}{10}=\dfrac3{10}$ , and "bases" equal to the values of $\ln t$ at both endpoints of each subinterval. The area of the trapezoid over the $i$ -th subinterval is

$\dfrac{\ln\ell_i+\ln r_i}2\dfrac3{10}=\dfrac3{20}\ln(ell_ir_i)$

Then the integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac3{20}\ln(\ell_ir_i)\approx\boxed{2.540}$

b. For the midpoint rule, we take the rectangle over each subinterval with base length equal to the length of each subinterval and height equal to the value of $\ln t$ at the average of the subinterval's endpoints, $\dfrac{\ell_i+r_i}2$ . The area of the rectangle over the $i$ -th subinterval is then

$\ln\left(\dfrac{\ell_i+r_i}2\right)\dfrac3{10}$

so the integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac3{10}\ln\left(\dfrac{\ell_i+r_i}2\right)\approx\boxed{2.548}$

c. For Simpson's rule, we find a quadratic interpolation of $\ln t$ over each subinterval given by

$P(t_i)=\ln\ell_i\dfrac{(t-m_i)(t-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+\ln m_i\dfrac{(t-\ell_i)(t-r_i)}{(m_i-\ell_i)(m_i-r_i)}+\ln r_i\dfrac{(t-\ell_i)(t-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

where $m_i$ is the midpoint of the $i$ -th subinterval,

$m_i=\dfrac{\ell_i+r_i}2$

Then the integral $I$ is equal to the sum of the integrals of each interpolation over the corresponding $i$ -th subinterval.

$I\approx\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}P(t_i)\,\mathrm dt$

It's easy to show that

$\displaystyle\int_{\ell_i}^{r_i}P(t_i)\,\mathrm dt=\frac{r_i-\ell_i}6(\ln\ell_i+4\ln m_i+\ln r_i)$

so that the value of the overall integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac{r_i-\ell_i}6(\ln\ell_i+4\ln m_i+\ln r_i)\approx\boxed{2.545}$

4 0

3 years ago

If i go into an ice cream parlor, and i have the choice of having one of 10 different flavors, with one of 5 different toppings

horrorfan [7]

35 hope this helps with the problem

7 0

3 years ago

A geneticist needs to grow a stock of fruit flies for her experiments.

antoniya [11.8K]

Answer :B

Step-by-step explanation:

200/1.8

\ $\sqrt{x}$

3 0

2 years ago

What is the solution to the system of equations?

alukav5142 [94]

Answer:

(x, y) = (-4, 15)

Step-by-step explanation:

The two equations have the same coefficient for y, so you can eliminate y by subtracting one equation from the other. Here the x coefficient is largest for the first equation, so it will work best to subtract the second equation.

(3x +y) -(2x +y) = (3) -(7)

x = -4 . . . . . . . . simplify

Now, we can find y by substituting this value for x.

2(-4) +y = 7

y = 7 +8 = 15 . . . . . add 8 to both sides of the equation

The solution is (x, y) = (-4, 15).

6 0

2 years ago

The equations of two functions are y=-21x+9 and y=24x+8 which function is changing more quickly? Explain

antoniya [11.8K]

Given:

The equations are

$y=-21x+9$

$y=24x+8$

To find:

Which function is changing more quickly.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where m is slope and b is y-intercept.

On comparing $y=-21x+9$ with the slope intercept form, we get

$m_1=-21$

$|m_1|=|-21|$

$|m_1|=21$

On comparing $y=24x+8$ with the slope intercept form, we get

$m_2=24$

$|m_2|=24$

Since, $|m_1|$ , it means the absolute rate of change of second function is greater than the first function.

Therefore, the second function is changing more quickly.

3 0

3 years ago