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tangare [24]
4 years ago
7

According to Charles's law, the volume of a gas will decrease as temperature decreases (directly proportional). Theoretically, a

gas will take up no volume when _______ has been reached.
Chemistry
1 answer:
a_sh-v [17]4 years ago
6 0

The answer is; absolute zero


Absolute zero is the lowest theoretical levels of temperatures that can be achieved in a system in thermodynamics. Theoretically also, an ideal gas at these temperatures has zero entropy and enthalpy  (meaning that its molecules have negligible vibrational motion).


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Which of the three has the largest ei1? which of the three has the largest ? 1s22s22p63s23p64s1 1s22s22p63s23p5 1s22s22p63s23p1?
coldgirl [10]

E_i1 will be largest for 1s^22s^22p^63s^23p^5.

Explanation: Ionization energy is the energy to knock off an electron from a gaseous atom of ion. First ionization energy or E_i1 is the energy required to remove 1 loosely held electron from 1 mole of gaseous atoms to produce 1 mole of gaseous ion carrying (+)1 charge.

M(g)\rightarrow M^+(g)+e^-

The electrons are filled according to Aufbau's rule and the orbitals which are strongly held to the nucleus follows the order s>p>d>f.

Electron is released from the outermost shell that is from the electrons which are loosely held to the nucleus, this follows the pattern s.

In configurations, 1s^22s^22p^63s^23p^64s^1,1s^22s^22p^63s^23p^5\text{ and } 1s^22s^22p^63s^23p^1

The loosely held orbital is 4s, therefore electron will be lost from that easily.

Now, in 3p orbital, one configuration has 5 electrons and one has 1 electron.

The configuration having 5 electrons will be more tightly held by the nucleus because it has more electrons that the one having only 1 electron. Hence, the electron will be lost easily from the configuration having 3p^1 as the valence shell.

Therefore, the configuration 1s^22s^22p^63s^23p^5 will the largest E_i1.


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