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My name is Ann [436]
3 years ago
7

Classifying Animals

Chemistry
2 answers:
MrMuchimi3 years ago
4 0

Answer:

I believe:

vertebrate: hummingbird, tiger, lobster

invertabrate: lizard, octopus, mosquito

Akimi4 [234]3 years ago
4 0

Answer:

Vertebrate lizard, hummingbird, tiger and the others are invertebrate

Explanation:

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A sample of gas in a balloon has an initial temperature of 21 ∘C and a volume of 1310 L . If the temperature changes to 70 ∘C ,
bixtya [17]

Answer:

1528.3L

Explanation:

To solve this problem we should know this formula:

V₁ / T₁ = V₂ / T₂

We must convert the values of T° to Absolute T° (T° in K)

21°C + 273 = 294K

70°C + 273 = 343K

Now we can replace the data

1310L / 294K = V₂ / 343K

V₂ = (1310L / 294K) . 343K → 1528.3L

If the pressure keeps on constant, volume is modified directly proportional to absolute temperature. As T° has increased, the volume increased too

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3 years ago
What is the Ring of Fire?
sesenic [268]

Answer:

D: chain of volcanoes circling the Pacific Basin

Explanation:

5 0
4 years ago
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!! ANSWER QUICK !!
kari74 [83]

Answer:

I can use a dichotomous key. It helps me classify objects by sorting it out with "yes" and "no" questions.

or

I can use a Punnett Square. It helps me classify what genes the offspring will receive simply by figuring out the recessive and dominant genes as well as the hetzygous and homzygous.

Now give an example of which ever chart you choose by drawing it if that is required. For the Punnett Square label each of the squares Top right Hetzygous, top left dominant, bottom left recessive, bot-tom right homzygous. And for the dichotomous key put a 5-7 length branch showing the animals that have fur, can breathe under water, what cannot or doesn't have those traits. or something similar

Hopefully this helps :)

3 0
3 years ago
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What is the volume, in milliliters, of 6.60 g of acetone?
UkoKoshka [18]
8.40 ml. I think that is right.
7 0
3 years ago
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Ag has an anomalous electron configuration. write the observed electron configuration of ag. express your answer in complete for
LUCKY_DIMON [66]

In Silver, the 4d orbitals will be completely filled. That implies that it does not have two electrons in the 5s orbital. The electronic configuration of Silver is :

Ag (47) = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^1 4d^10

8 0
4 years ago
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