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mario62 [17]
3 years ago
12

Write the oxidation number for the following elements: for brainliest answer

Chemistry
1 answer:
ollegr [7]3 years ago
6 0

Explanation:

Here's an oxidation chart to help

..................

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What STARTING element undergoes alpha decay to yield uranium-234 (U) as a PRODUCT?
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Uranium-238 is the element that undergoes decay to yield uranium-234
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Two processes are described below: Process A: rapid moving water strikes a rock on the bottom of a stream and breaks it into pie
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Answer:

both represent physical  weathering

Explanation:

7 0
3 years ago
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How does changing the amount of one substance affect a mixtures identity and a compounds identity iscience?
pychu [463]

Explanation:

A compound is defined as follows.

  • Compounds are pure substance.
  • The atoms bonded in a compound are in specific proportion.
  • A compound is formed by chemical combination.
  • For a compound, melting point and boiling point is defined.

A mixture is defined as follows.

  • Mixtures are impure substance.
  • The bonded atoms in a mixture are in any proportion.
  • A mixture is formed by physical combination.
  • For a mixture, melting point and boiling point is not defined.

On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures  as atoms can be bonded in any proportion in a mixture.

5 0
2 years ago
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(b) What is the pH of 0.40 M triethylammonium chloride, CH₃ (CH₂)₃ NHCl ?
Valentin [98]

pH of 0.40M triethylammonium chloride is 5.90.

<h3>What is pH?</h3>

A solution's acidity may be determined by looking at its pH, which is a measurement of hydrogen ion concentration. Pure water slightly separates into ions with roughly equal amounts of hydrogen and hydroxyl (OH) ions. [H+] is 107 for a neutral solution, or pH = 7.

<h3>Given : </h3>

Concentration of triethylammonium chloride = 0.40M

pH = ?

<h3>Solution: </h3>

(CH3CH2)3NHCl ------> (CH3CH2)3NH⁺ + Cl⁻

(CH3CH2)3NH⁺ will react with water to give H3O⁺ .

(CH3CH2)3N will have a Kb = 5.2 x 10 ^(-4)

Kw = Kb x Ka

=> Ka = Kw / Kb = 10^(-14) / 5.2 x 10 ^(-4)

=> Ka = 1.92 x 10^(-11)

so by the reaction we have ,

Ka = x²/(0.40 - x)

=> x = 1.2393 x 10 ^(-6)

now, pH = -log( [H3O⁺]) = - log ( 1.2393 x 10 ^(-6)) = 5.906

To learn more about pH :

brainly.com/question/15289741

#SPJ4

5 0
1 year ago
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