I got 77 for my total answer. I correct? if not can some help
2 answers:
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Answer:
3/7 is the smallest
Step-by-step explanation:
after we take the LCM of both the denominators and then compare their resulted numerator and denominator we get that 3/7 is the smallest
Try this:
x³+4x²+x-6=0
1) To re-write the equation into form:
1*x³+4*x²+1*x-6=0, the note 1+4+1=6, it means x=1
2) to re-write the equation into form:
(x-1)(x²+5x+6)=0
(x-1)(x+2)(x+3)=0
3)
Answer: -3;-2;1.
x³+4x²+x-6=0
1) To re-write the equation into form:
1*x³+4*x²+1*x-6=0, the note 1+4+1=6, it means x=1
2) to re-write the equation into form:
(x-1)(x²+5x+6)=0
(x-1)(x+2)(x+3)=0
3)
Answer: -3;-2;1.