Amount financed
320−100=220

Total paid
100+25×12=400

Interest paid
400−320=80

Interest rate=(2yc)÷(m (n+1))
I=(2×12×80)÷(220 (12+1))
I=(2×12×80)÷(220×13)
I=0.67×100
I=67%

4 0

3 years ago

Read 2 more answers

If the interest rate on a savings account is 0.018%, approximately how much money do you need to keep in this account for 1 year

Diano4ka-milaya [45]

We are not told how often the interest is compounded, so assuming it is compounded yearly, you need to keep $9.99 in the account to pay the fee.

Explanation: 
Compound interest follows the formula A=p(1+r)^t,
where:
A is the total amount in the account,
p is the amount of principal,
r is the interest rate as a decimal number,
and t is the number of years.

For our problem: 
A = 9.99,
p is unknown,
r = 0.018% = 0.00018,
and t=1.

This gives us: 
9.99=p(1+0.00018)^1;
9.99=p(1.00018).

Divide both sides by 1.00018: 
9.99=p.

3 0

3 years ago

Read 2 more answers

Type the correct answers out, thank you - 20 POINTS

nadezda [96]

AB and BC form a right angle at their point of intersection. This means AB is perpendicular to BC.

We are given the coordinates of points A and B, using which we can find the equation of the line for AB.

Slope of AB will be:

$m= \frac{-1-1}{14-2}=-1/6$

Using this slope and the point (2,1) we can write the equation for AB as:

$y-1= \frac{-1}{6}(x-2) \\ \\ 
y= -\frac{1}{6}x+ \frac{1}{3}+1 \\ \\ 
y=-\frac{1}{6}x+ \frac{4}{3} 
$

The above equation is in slope intercept form. Thus the y-intercept of AB is 4/3.

Slope of AB is -1/6, so slope of BC would be 6. Using the slope 6 and coordinates of the point B, we can write the equation of BC as:

y - 1 = 6(x - 2)
y = 6x - 12 + 1
y = 6x - 11

Point C lies on the line y = 6x - 11. So if the y-coordinate of C is 13, we can write:

13 = 6x - 11
24 = 6x
x = 4

The x-coordinate of point C will be 4.

Therefore, the answers in correct order are:

4/3 , 6, -11, 4

8 0

3 years ago