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anastassius [24]
3 years ago
13

middle" class="latex-formula">
3​
Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0
96
____________________
You might be interested in
A bookcase measures 13 ft wide and 24 ft tall. What would the bookcase's measurements be on a scale drawing using the scale 3 cm
qaws [65]

Answer:

19.5 cm wide

36 cm tall

Step-by-step explanation:

The given, 3 cm : 2 ft, is your first fraction (3 cm / 2 ft). We need to figure out how many cm is 13 ft and 24 ft. Let's start with 13 ft. We would use the first fraction, 3 cm / 2 ft, is equal to x cm / 13 ft. Then, you would cross multiply and get an answer of 19.5 cm. Now, we do the same thing but instead of 13 ft we need to use 24 ft. So again, 3 cm / 2 ft is equal to x cm / 24 ft. Then, cross multiply and get a final answer of 36 cm.

6 0
3 years ago
Read 2 more answers
If f(x)=x+8 and g(x)=-4x-3 find (f+g)(x)
nydimaria [60]

Answer:

for this case we have the following functions:

f (x) = x + 8

g (x) = -4x - 3

Subtracting the functions we have:

(f - g) (x) = f (x) - g (x)

(f - g) (x) = (x + 8) - (-4x - 3)

Rewriting:

(f - g) (x) = x + 8 + 4x + 3

(f - g) (x) = 5x + 11

Answer:

D. (f - g) (x) = 5x + 11

7 0
3 years ago
What is the slope of the line that contains the points (-1,8) and (2,-4)<br><br>HELPPPPPP!!!
katrin [286]

Step-by-step explanation:

a =  \frac{ - 4 - 8}{2 -  ( - 1)}  =  \frac{ - 12}{3}  =  - 4

7 0
3 years ago
Find the area of the region in the first quadrant bounded on the left by the ​y-​axis, below by the line y equals one third x co
bonufazy [111]

Answer:

The bounded area  is: \frac{73}{6}\approx 12.17

Step-by-step explanation:

Let's start by plotting the functions that enclose the area, so we can find how to practically use integration. Please see attached image where the area in question has been highlighted in light green. The important points that define where the integrations should be performed are also identified with dots in darker green color. These two important points are: (2, 6) and (3, 1)

So we need to perform two separate integrals and add the appropriate areas at the end. The first integral is that of the difference of function y=x+4 minus function y=(1/3)x , and this integral should go from x = 0 to x = 2 (see the bottom left image with the area in red:

\int\limits^2_0 {x+4-\frac{x}{3} } \, dx =\int\limits^2_0 {\frac{2x}{3} +4} \, dx=\frac{4}{3} +8= \frac{28}{3}

The next integral is that of the difference between y=-x^2+10 and the bottom line defined by: y = (1/3) x. This integration is in between x = 2 and x = 3 (see bottom right image with the area in red:

\int\limits^3_2 {-x^2+10-\frac{x}{3} } \, dx =-9+30-\frac{3}{2} -(-\frac{8}{3} +20-\frac{2}{3} )=\frac{39}{2} -\frac{50}{3} =\frac{17}{6}

Now we need to add the two areas found in order to get the total area:

\frac{28}{3} +\frac{17}{6} =\frac{73}{6}\approx 12.17

8 0
3 years ago
The probability of choosing a winning card from a stack of cards is 5.3%.
drek231 [11]

Answer:

94.7%

Step-by-step explanation:

If it is only winning or losing cards, then you can subtract 5.3 from 100 because probability is out of 100%

100-5.3 = 94.7

8 0
3 years ago
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